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alukav5142 [94]
4 years ago
6

What happens when you add seven and three, then multiply that by two?

Mathematics
1 answer:
rusak2 [61]4 years ago
4 0

Answer:  20

Step-by-step explanation:

7 + 3 = 10

10 x 2 = 20

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Need some assistance with the following problem.
Lisa [10]

Answer:

The provided statement \exists x(x^2-4=1) is true in the domain of real number.

Step-by-step explanation:

Consider the provided information.

Any equation or inequality with variables in it is a predicate in the domain of real numbers.

The provided statement is:

\exists x(x^2-4=1)

Here, we need to find the value of x for which the above statement is true.

Since the value of x can be any real number so we can select the value of x as √5

(√5)²-4=1

5-4=1

Which is true.

Thus, the provided statement \exists x(x^2-4=1) is true.

7 0
3 years ago
If f(x)=x-6 and g(x)=x^3, find G(f(x)) a)x^3(x-7) b)x^3-7 c)x^3+x-7 d)(x-7)^3
nirvana33 [79]

Answer:

(x-6)^3

Step-by-step explanation:

f(x)=x-6 \\\\g(x)=x^3 \\\\g(f(x))=(x-6)^3

Hope this helps!

4 0
3 years ago
I will give brainliest I promise
Fed [463]
A is the correct answer
6 0
4 years ago
During a track meet, Calvin drinks 0.6 liters of water. Melinda drinks 0.8 times as much water as Calvin during the track meet.
Mariulka [41]

Answer:

Step-by-step explanation:

Easy 0.6 times 0.8 = 0.48

3 0
3 years ago
What is the volume of a hemisphere with a radius of 48 m, rounded to the nearest tenth of a cubic meter
Thepotemich [5.8K]

Answer:

The volume of the hemisphere is approximately 231,623.3 m³

Step-by-step explanation:

The radius of the hemisphere in the question, r = 48 m

A hemisphere is obtained by sharing a sphere into two halves

The radius of the hemisphere = The radius of the sphere which describes it

∴ The volume of a hemisphere = The volume of a sphere ÷ 2

The volume of a sphere = (4/3)·π·r³

∴ The volume of a hemisphere = (4/3)·π·r³ ÷ 2 =  (2/3)·π·r³

∴ The volume of the given hemisphere with 48 m radius, V = (2/3) × π × 48³

∴ V = (2/3) × π × (48 m)³ = 231,623.343164 m³

When the measure of the volume of the hemisphere is rounded to the nearest tenth, we have, V ≈ 231,623.3 m³.

5 0
3 years ago
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