Answer:
6 x 6 x 3 cm
Step-by-step explanation:
The base of the box needs to fit the base of the hemisphere.
The maximum width and length of the hemisphere is the diameter of the base of the hemisphere (which is circular)
Diameter of a circle = 2r
As the radius = 3 cm, the diameter = 2 x 3 = 6 cm
Therefore, the width and length of the box should both be 6cm
The height of the box needs to accommodate the height of the hemisphere. The height of the hemisphere is the radius, so the height of the box should be 3 cm.
Therefore, the dimensions of the box should be 6 x 6 x 3 cm
I hope this helps you
30 degree = k
60 degree = k square root of 3
90 degree = 2k
hypothenus =10 =>90 degree
one leg = 5 => 30 degree
L=7+w
P=(12x+14)=2(6x+7)
l+w= P/2 = 2(6x+7)/2= 6x+7
l+w=6x+7
2l = 6x+7
l = (6x+7)/2
l=7+w
-> w= l-7
= [(6x+7)/2] -7
= (6x+7-14)/2
= (6x-7)/2
If we draw RU and RT we see the radii are perpendicular to the tangents, so TRU and TZU are supplementary. Since TZU=XZY=15 degrees, TRU=180-15=165 degrees. So the other side is 360-165=195 degrees as is the measure of arc TSU
Answer: 195 degrees
