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Scorpion4ik [409]
3 years ago
14

A human cell has a mutation in the gene that encodes the enzyme that generates lactate from pyruvate, rendering that enzyme comp

letely non-functional.
Assuming that there is ample glucose present, how would this cell generate energy in the presence of oxygen?

A) Glycolysis coupled with ethanol fermentation.
B) Aerobic respiration.
C) Primarily through the break down of proteins into amino acids.
D) This cell would have no way to generate energy under these conditions. because it cannot carry out the reactions needed for glycolysis
Biology
1 answer:
Liono4ka [1.6K]3 years ago
7 0

Answer:

<h2>B</h2>

Explanation:

Glycolysis is the process of production of pyruvate from glucose by various enzymatic steps.

This pyruvate is further used in different ways;  as it is differently used in the presence of oxygen or in the absence of oxygen.

In the absence of oxygen, lactate is generated form  pyruvate, as given here, if this enzyme is non-functional, then lactate would not be produced.

In the presence of oxygen, pyruvate is oxidized in TCA cycle and finally through electron transport chain, energy in generated.

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Answer:

1. Chromatin condense into chromosomes.

4. Homologous chromosomes pair up (formation of tetrads).

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Explanation:

This question portrays the process of meiosis in a cell. The ordered sequence of events in the options are:

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5. Homologous chromosomes separate and move to poles - This process characterizes the Anaphase stage of meiosis I. Homologous chromosomes are pulled apart to opposite poles of the cell by spindle microtubules.

2. Sister chromatids separate - After meiosis I, meiosis II involving sister chromatids instead of homologous chromosomes follows. In the Anaphase stage of meiosis II specifically, sister chromatids are pulled apart towards opposite poles of the cell.

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by the nitrocellulose membrane filter method. (more info below)

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hope this helped!

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