The answer would be gas I believe
Answer:
- GLYCOLYSIS :- Glycolysis is the metabolic pathway that converts glucose C₆H₁₂O₆, into pyruvic acid, CH₃COCOOH. The free energy released in this process is used to form the high-energy molecules adenosine triphosphate and reduced nicotinamide adenine dinucleotide
- PRODUCTS :- Glycolysis produces 2 ATP, 2 NADH, and 2 pyruvate molecules: Glycolysis, or the aerobic catabolic breakdown of glucose, produces energy in the form of ATP, NADH, and pyruvate, which itself enters the citric acid cycle to produce more energy.
- INPUT:- Glycolysis is the first step in cellular respiration, occurring in all living cells. Overall, the input for glycolysis is one glucose, two ATP and two NAD+ molecules giving rise to two pyruvate molecules, four ATP and two NADH.
- BREAKDOWN:- During glycolysis, glucose ultimately breaks down into pyruvate and energy; a total of 2 ATP is derived in the process (Glucose + 2 NAD+ + 2 ADP + 2 Pi --> 2 Pyruvate + 2 NADH + 2 H+ + 2 ATP + 2 H2O). The hydroxyl groups allow for phosphorylation. The specific form of glucose used in glycolysis is glucose 6-phosphate
- STAGES:-
- Reaction 1: glucose phosphorylation to glucose 6-phosphate.
- Reaction 2: isomerization of glucose 6-phosphate to fructose 6-phosphate
- Reaction 3: phosphorylation of fructose 6-phosphate to fructose 1,6-bisphosphate
- Reaction 4: cleavage of fructose 1,6-bisphosphate into two three-carbon fragments.
Explanation:
<h2>HOPE IT HELPS YOU ITZ ADMIRER </h2>
Parasite: Parasites are different from predators because parasites only take resources from one host, whereas predators eat many prey. A good example of this is the trematode parasite Schistosoma mansoni. An adult schistosome parasite lives inside of just one human host
Answer: The two possible explanation for the outcome are as follows:
Explanation:
1. The bacterial DNA in the pellet was not completely isolated properly, therefore, no fluorescence was observed in the pellet under the exposure of UV radiation.
2. After 3 hours of induction with the IPTG and labeling with the G3. The IPGT might not be able to bound to the bacterial DNA that could show response of fluorescence in the ultraviolet light.