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Tcecarenko [31]
3 years ago
6

Instructions: Select the correct answer.

Mathematics
1 answer:
zepelin [54]3 years ago
5 0
= 18 1/5 + 22 2/5 + 40 1/5
answer is D. last one
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#10-12!!! look at picture!!! I don't give out points for free!!! T.T
Tom [10]
F(x)=x
Domain: 1 2 3 4 5 6
Range: 1 2 3 4 5 6

F(x)=2x
Domain: 1 2 3 4
Range: 0 2 4 6
3 0
3 years ago
Read 2 more answers
How do you figure out this equation?
maw [93]
Equation of a circle is (x-x1)+(y-y1)=r²
when x1 and y1 are the coordinates of the centre

So you can substitute the centre in to get (x-5)²+(y+9)²=r²

When you draw a diagram it's obvious the radius is 9

9²=81

Therefore equation is (x-5)²+(y+9)²=81

Any questions, just ask :)

6 0
2 years ago
Please help me prove this theorem thing. I'll give yuh mind kisses <3 have a good day luvlies
lesantik [10]

Answer:

∠ 1 = 20 x + 5

∠ 2 = 24 x - 1

If lines l and m are parallel:

∠ 1 + ∠ 2 = 180°

20 x + 5 + 24 x - 1 = 180

44 x + 4 = 180

44 x = 180 - 4

44 x = 176

x = 176 : 44

x = 4°

Your welcome again :)

Step-by-step explanation:

6 0
3 years ago
Please help!! MathsWatch, Surd Expressions, Clip 207c
dexar [7]

Answer:

A=(72+36\sqrt{3})\ mm^2

Step-by-step explanation:

see the attached figure with letters to better understand the problem

Let

a ----> the height of rectangle in mm

b ---> the base of rectangle in mm

step 1

Find the base of rectangle

b=AB+BC+CD+DE ----> by segment addition postulate

substitute

b=3+3+3+3=12\ mm

step 2

Find the height of rectangle

a=FB+CG+GH ---> by segment addition postulate

substitute the given values

a=3+CG+3\\a=6+CG

Find the length sides CG

Applying the Pythagorean Theorem

BG^2=BC^2+CG^2

substitute the given values

6^2=3^2+CG^2

CG^2=6^2-3^2

CG=\sqrt{27}\ mm

simplify

CG=3\sqrt{3}\ mm

therefore

a=(6+3\sqrt{3})\ mm

step 3

Find the area of rectangle

A=ab

we have

a=(6+3\sqrt{3})\ mm

b=12\ mm

substitute

A=(6+3\sqrt{3})(12)=(72+36\sqrt{3})\ mm^2

8 0
3 years ago
Help me rickroll you
skelet666 [1.2K]

Answer:

Shoyo here!

Step-by-step explanation:

wow.

5 0
3 years ago
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