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bezimeni [28]
3 years ago
7

Can somebody help me

Mathematics
1 answer:
S_A_V [24]3 years ago
4 0

Answer:

correct me if i'm wrong i pretty sure its C

Step-by-step explanation:


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Make sure u have explanation pls
Orlov [11]
Narrow
it describes a path lined with flowers
4 0
3 years ago
Find ​(a) the slope of the curve at the given point​ p, and ​(b) an equation of the tangent line at p. y=−2−9x2​; ​p(2​,−38​)
Neporo4naja [7]

Answer:

a) -36

b) y = -36x +34

Step-by-step explanation:

a) The slope is found using the derivative of the function.

  f'(x) = dy/dx = 0 -9(2x) = -18x

Then at x=2, the slope is ...

  f'(2) = -18·2 = -36

___

b) The point-slope form of the equation can be written as ...

  y = -36(x -2) -38

Simplifying to slope-intercept form, we get ...

  y = -36x +34

6 0
3 years ago
Please calculate this limit <br>please help me​
Tasya [4]

Answer:

We want to find:

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n}

Here we can use Stirling's approximation, which says that for large values of n, we get:

n! = \sqrt{2*\pi*n} *(\frac{n}{e} )^n

Because here we are taking the limit when n tends to infinity, we can use this approximation.

Then we get.

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} =  \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}

Now we can just simplify this, so we get:

\lim_{n \to \infty} \frac{1}{e} *\sqrt[2*n]{2*\pi*n} \\

And we can rewrite it as:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n}

The important part here is the exponent, as n tends to infinite, the exponent tends to zero.

Thus:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n} = \frac{1}{e}*1 = \frac{1}{e}

7 0
3 years ago
#7 - #9 theres the pic
Ratling [72]
#7
2,4,8,16
15,30,60,120

#9
1,2,3,
4,8,12
6 0
3 years ago
Please help me if you can. Please also write how you got the answer thank you.
vaieri [72.5K]

Answer:

The three numbers are 341, 342, and 343

Step-by-step explanation:

We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 1026. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 1026

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 1026

3X + 3 = 1026

3X + 3 - 3 = 1026 - 3

3X = 1023

3X/3 = 1023/3

X = 341

Which means that the first number is 341, the second number is 341 + 1 and the third number is 341 + 2. Therefore, three consecutive integers that add up to 1026 are 341, 342, and 343.

341 + 342 + 343 = 1026

We know our answer is correct because 341 + 342 + 343 equals 1026 as displayed above.

6 0
2 years ago
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