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Anton [14]
4 years ago
6

What are some structural explanation for why animal and plant cells differ in response to changes in the extracellular space?

Biology
1 answer:
Brums [2.3K]4 years ago
4 0

Answer:

The animal cells produce the collagen but the plant cell does not produce collagen that responsible for producing the complex structure of protein and carbohydrates that is called extracellular matrix cell. Collagen is an important protein that provides strength to the structural integrity. On the other hand, the plant has not collagen so they have their extracellular supportive structure. The cell wall is so rigid and covered by the cell that protects it that provides shape and support to it. The plant cell also made up of molecules and these are called cellulose. These cellulose structured into the fibers that are called micro-fibrils

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Dr. Brooke studies plants to learn about ecosystems. What is Dr. Brooke's specialty?
wariber [46]

Answer:

Ecologist

Explanation:

"Ecologists study the interrelationships between organisms and their environments." (Environmentalscience.org)

3 0
3 years ago
What keeps intracellular receptors from binding to dna before a hormone binds to the receptor?.
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Answer:

chaperone proteins (chaperonins)

Explanation:

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2 years ago
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Endocrine cells
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b

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Bacteria would be considered a(n) species. <br><br> r- selected<br> K-selected
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It would be a fungus
5 0
3 years ago
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A population is made up of individuals where 77 have the A1A1 genotype, 65 have the A1A2 genotype, and 123 have the A2A2 genotyp
lana [24]

Answer:

Frequency of allele A1- 0.41

Explanation:

In Hardy weinberg equilibrium,

P refers to the dominant allele

q refers to the recessive allele

The allele frequency will be p+q=1

The genotypic frequency is- P²+q²+2pq=1

P²= genotype of dominant trait ( A1A1)- 77

2pq= genotype of heterozygotes (2pq)- 65

q²= genotype of recessive trait (A2A2)-  123

Total number of offsprings= 77+  65+ 123

                                            = 265

Now to calculate allele frequency of A1=

\dfrac{\text{number of A1A1 offspring}}{ \text{total number of offspring}}+\dfrac{1}{2}(\dfrac{\text{number of A1A2 offspring}}{\text{total number of offspring}})

= 77/265 + 1/2( 65//265)

=  0.290+ 0.122

= 0.413

Thus, 0.41 is correct.

3 0
3 years ago
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