The question is telling you that the length of the rectangle is 3 metres more than twice the width.
So let:
<em>w= width</em>
<em>L= length</em>
Because the length is 3 metres more than twice<em> </em>the width: <em>L= </em><em>2</em><em>w+</em><em>3</em>
They also tell you the perimeter is 48 metres.
<em>P= L+L+w+w</em>
So the equation of the perimeter is:
<em>48= (2w+3)+(2w+3)+2w +2w</em>
<em>48= 2(2w+3) + 4w</em>
To find w, expand and simplify.
<em>48= 4w+6+4w</em>
<em>48= 8w + 6</em>
<em>42= 8w</em>
<em>5.25=w</em>
Now that you know the width, plug in the value into the length equation:
<em>L= 2w+3</em>
<em>L=2(5.25)+3</em>
<em>L=10.50+3</em>
<em>L=13.5</em>
If I am wrong let me know! I hope this helps.
Answer:
a) 1/800 or 0.00125
b) i) 0.0013
ii) 0.001
c) 60%
Step-by-step explanation:
T = [tan(2×30)+1][2cos(30)-1] ÷ (y²-x²)
T = (tan60 + 1)(2cos30 - 1) ÷ (41² - 9²)
T = (sqrt(3) + 1)(sqrt(3) - 1) ÷ 1600
T = (3-1)/1600
T = 2/1600
T = 1/800
T = 0.00125
Error: 0.002 - 0.00125
0.00075
%error
0.00075/0.00125 × 100
60%
Answer:
<em>14 miles</em>
Step-by-step explanation:
It's still 14 miles no matter which way you go.
Y=mx+b
m=slope
b=y itnercept
remember the points go in (x,y) form
also, an easy way to find points is to subsitute values for x andn get values for y
so
6. y=5x-1
some points are (0,-1) (1,4) (2,9) (314)
7. y=-x+8
some points are (0,8) (1,7) (2,6) (3,5)
8. y=0.2x+.3
somepoints are (0,0.3) (1,0.5) (2,0.7) (3,0.9)
9. y=1.5x-3
somepoints are (0,-3) (1,-1.5) (2,0) (3,1.5)
10. y=-1/2x+4
somepoints are (0,4) (1,7/2) (2,3) (3,5/2)
11. y=2/3x-5
some points are (0,-5) (1,-13/3) (2,-11/3) (3,-3)
