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pishuonlain [190]

3 years ago

10

Line A passes through the points (1,2) and (3,6). what is the slope of a line parallel to line A.

2 answers:

Alona [7]3 years ago

3 0

Y = mx + b
y = 2x
Slope is 2

nataly862011 [7]3 years ago

3 0

Hello!

Step-by-step explanation:

$Slope=\frac{Y_2-Y_1}{X_2-X_1}$

$\frac{6-2}{3-1}=\frac{4}{2}=2$

<u><em>Slope is 2.</em></u>

<u><em>2 is the final answer.</em></u>

Hope this helps you!

Have a nice day! :)

:D

-Charlie

Thanks!

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A parabola can be represented by the equation x2 = -20y.

aliya0001 [1]

Answer:

$\mathrm{Parabola\:focus\:given}\:x^2=-20y:\quad \left(0,\:-5\right)$

Step-by-step explanation:

Given the equation

$x2 = -20y$

A parabola is the locus of points such that the distance to a point the focus equals the distance to a line the directrix.

$4p\left(y-k\right)=\left(x-h\right)^2$ is the standard equation for an up-down facing parabola with vertex at (h, k), and a focal length |p|.

so

$x^2=-20y$

$\mathrm{Switch\:sides}$

$-20y=x^2$

$\mathrm{Factor\:}4$

$4\cdot \frac{-20}{4}y=x^2$

$4\left(-5\right)y=x^2$

$\mathrm{Rewrite\:as}$

$4\left(-5\right)\left(y-0\right)=\left(x-0\right)^2$

$\left(h,\:k\right)=\left(0,\:0\right),\:p=-5$

Parabola is symmetric around the y-axis and so the focus lies a distance\ p from the center (0, 0) along the y-axis.

$\left(0,\:0+p\right)$

$=\left(0,\:0+\left(-5\right)\right)$

$\mathrm{Refine}$

$\left(0,\:-5\right)$

Therefore,

$\mathrm{Parabola\:focus\:given}\:x^2=-20y:\quad \left(0,\:-5\right)$

Please check the attached figure too.

6 0

3 years ago

Read 2 more answers