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emmainna [20.7K]
3 years ago
8

There are 46 students in the after-school tutoring program that starts at 3pm and ends at 4pm. 19

Mathematics
2 answers:
Slav-nsk [51]3 years ago
8 0

Answer:

58.69

Step-by-step explanation:

maybe you can try

Semmy [17]3 years ago
5 0

Answer:

what idu

Step-by-step explanation:

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Given x+2y=-6 solve for y
Varvara68 [4.7K]
You take the x and change it to the other side to leave y by itself and then divide by 2 = Y=-3-x
7 0
2 years ago
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You do not need to flip the inequality sign when solving the inequality -3t + 7 ≥ 9. True False
nordsb [41]
Hello!

It is False because t is multiplied by a negative number, so to solve for it you will need to divide both sides by -3 which mean you have to flip the sign. 

Hope this helps!
7 0
2 years ago
Simplify the radical of 200 squared
Thepotemich [5.8K]

Answer:

The answer is 10√2.

Step-by-step explanation:

7 0
3 years ago
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Find the length of the following curve. If you have a​ grapher, you may want to graph the curve to see what it looks like.
stepladder [879]

The length of the curve y = \frac{1}{27}(9x^2 + 6)^\frac 32 from x = 3 to x = 6 is 192 units

<h3>How to determine the length of the curve?</h3>

The curve is given as:

y = \frac{1}{27}(9x^2 + 6)^\frac 32 from x = 3 to x = 6

Start by differentiating the curve function

y' = \frac 32 * \frac{1}{27}(9x^2 + 6)^\frac 12 * 18x

Evaluate

y' = x(9x^2 + 6)^\frac 12

The length of the curve is calculated using:

L =\int\limits^a_b {\sqrt{1 + y'^2}} \, dx

This gives

L =\int\limits^6_3 {\sqrt{1 + [x(9x^2 + 6)^\frac 12]^2}\ dx

Expand

L =\int\limits^6_3 {\sqrt{1 + x^2(9x^2 + 6)}\ dx

This gives

L =\int\limits^6_3 {\sqrt{9x^4 + 6x^2 + 1}\ dx

Express as a perfect square

L =\int\limits^6_3 {\sqrt{(3x^2 + 1)^2}\ dx

Evaluate the exponent

L =\int\limits^6_3 {3x^2 + 1} \ dx

Differentiate

L = x^3 + x|\limits^6_3

Expand

L = (6³ + 6) - (3³ + 3)

Evaluate

L = 192

Hence, the length of the curve is 192 units

Read more about curve lengths at:

brainly.com/question/14015568

#SPJ1

7 0
1 year ago
Suppose y = sqrt 2x+1, where x and y are functions of t.
frutty [35]

If y = √(2x + 1), then differentiating both sides implicitly with respect to t gives

dy/dt = 1/2 • 1/√(2x + 1) • 2 • dx/dt = 1/√(2x + 1) • dx/dt

(a) If dx/dt = 9 and x = 4, then

dy/dt = 1/√(2•4 + 1) • 9

dy/dt = 1/√(8 + 1) • 9

dy/dt = 1/√9 • 9

dy/dt = 9/3

dy/dt = 3

(b) If dy/dt = 3 and x = 40, then

3 = 1/√(2•40 + 1) • dx/dt

3 = 1/√(80 + 1) • dx/dt

3 = 1/√81 • dx/dt

3 = 1/9 • dx/dt

dx/dt = 27

5 0
2 years ago
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