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2 years ago

11

PLEASE ANSWER ASAP! IMPORTANT! MUST BE CORRECT! GIVING OUT POINTS!

2 answers:

mr Goodwill [35]2 years ago

7 0

So an even number is represented as 2n where n= a whole number
an odd is 1 more than an even so 2n+1 is odd

so even+odd=2n+2n+1=4n+1=
we see 2 2n's in there which are even
(even)+(even)+1
we know that even+even=even try that withe any 2 even numbers
then +1 means it's odd so therefor it is always true

Keith_Richards [23]2 years ago

5 0

Try adding some of these together to look for the pattern:

<span>-13 +16 = 3 odd+even = odd </span>

<span>-7 + 16 = 9 </span>

<span>how about -13 + -7 = -20 </span>

<span>-8 + 16 = 8 </span>

<span>It looks like </span>

<span>even + even = even </span>
<span>odd + odd = even </span>

<span>even + odd = odd </span>

<span>So, we only get an odd result in this case. It seems that it is always true.</span>

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I NEED HELP PLEASE EXPLAIN

kari74 [83]

Answer:

The function concerning the evolution of the value of the first car is exponential and the one concerrning the value of the second car is linear

Step-by-step explanation:

1st car's drop in value ( not considering the second hand type of drop):

1.4500$

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6 0

2 years ago

Someone please help me

allsm [11]

Answer:

Solutions: $x = \frac{-3}{ 4} + i \sqrt{39}$ , $x = \frac{-3}{4} - i \sqrt{39}$

Step-by-step explanation:

Given the quadratic equation, 2x² + 3x + 6 = 0, where a =2, b = 3, and c = 6:

Use the <u>quadratic equation</u> and substitute the values for a, b, and c to solve for the solutions:

$x = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}$

$x = \frac{-3 +/- \sqrt{3^{2} - 4(2)(6)} }{2(2)}$

$x = \frac{-3 +/- \sqrt{9- 48} }{4}$

$x = \frac{-3 +/- \sqrt{-39} }{4}$

$x = \frac{-3 + i \sqrt{39} }{4}$ , $x = \frac{-3 - i \sqrt{39} }{4}$

Therefore, the solutions to the given quadratic equation are:

$x = -\frac{3}{ 4} + i \sqrt{39}$ , $x = -\frac{3}{4} - i \sqrt{39}$

4 0

2 years ago

180 lb 12 oz - 79.3 kg = ___________ kg

Brrunno [24]

Answer:

$180lb\ 12 oz - 79.3kg = 2.8kg$

Step-by-step explanation:

Given

$180\ lb 12\ oz - 79.3kg$

Required

Solve

First, convert 180lb to kg

$1lb \to 0.454kg$

$180lb \to 180 *0.454kg$

$180lb \to 81.7kg$ -- to 1dp

Next, convert 12oz to kg

$1oz \to 0.03kg$

$12oz \to 12 * 0.03kg$

$12oz \to 0.4kg$ --- to 1 dp

So, the expression becomes:

$180\ lb 12\ oz - 79.3kg$

$81.7kg + 0.4kg - 79.3kg$

$= 2.8kg$

Hence:

$180lb\ 12 oz - 79.3kg = 2.8kg$

3 0

2 years ago