Answer:
The total trip will be 4 hours long.
Step-by-step explanation:
The length of the trip decreases by 65/2 miles for every half hour. So in 2 half hours (or 1 hour), Aubree would have traveled the last 65 miles she needed.
Answer:
x=18°
Step-by-step explanation:
5x-18=4x
subtract 4x from both sides
x-18=0
add 18 to both sides
x=18°
Answer:
33×33+33-33÷0=infinity
33×33=1089
33-33=0
Taking L.H.S
=33×33+(33-33)÷0
=1089+0÷0
=1089÷0
=infinity
L.H.S=R.H.S
Step-by-step explanation:
The solutions of the inequality is 7.99<x<8.01. I think this solutions means the radius of hole in the bolt or something along that, but I'm not sure.
Using the normal distribution, it is found that:
- 3 - a) The 40th percentile of the height of Dinaric Alps distribution for men is of 72.2 inches.
- 3 - b) The minimum height of man in the Dinaric Alps that would place him in the top 10% of all heights is of 76.84 inches.
- 4 - a) The 25th percentile for the math scores was of 71.6 inches.
- 4 - b) The 75th percentile for the math scores was of 78.4 inches.
<h3>Normal Probability Distribution
</h3>
In a <em>normal distribution </em>with mean and standard deviation , the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
Question 3:
- The mean is of 73 inches, hence .
- The standard deviation is of 3 inches, hence .
Item a:
The 40th percentile is X when Z has a p-value of 0.4, so <u>X when Z = -0.253</u>.
The 40th percentile of the height of Dinaric Alps distribution for men is of 72.2 inches.
Item b:
The minimum height is the 100 - 10 = 90th percentile is X when Z has a p-value of 0.9, so <u>X when Z = 1.28</u>.
The minimum height of man in the Dinaric Alps that would place him in the top 10% of all heights is of 76.84 inches.
Question 4:
- The mean score is of 75, hence .
- The standard deviation is of 5, hence .
Item a:
The 25th percentile is X when Z has a p-value of 0.25, so <u>X when Z = -0.675</u>.
The 25th percentile for the math scores was of 71.6 inches.
Item b:
The 75th percentile is X when Z has a p-value of 0.25, so <u>X when Z = 0.675</u>.
The 75th percentile for the math scores was of 78.4 inches.
To learn more about the normal distribution, you can take a look at brainly.com/question/24663213