Answer:
The equation is given below as

Step 1:
We will work on the left-hand side, we will have

By substituting the identity above, we will have

Here, we will make use of the quotient identity
Step 2:
By writings an expression, we will have

Here, we will use the definition of subtraction

Step 3:
We will apply the double number identity given below

By applying this, we will have

Here, we will use the double number identity