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3 years ago

Subtract, 8 3/8 - 10 1/6

1 answer:

5 0

$8\frac{3}{8} = \frac{67}{6} \\ 10\frac{1}{6} = \frac{61}{6}$

$8\frac{3}{8} - 10\frac{1}{6}$

$convert$ them to: $\frac{67}{8} - \frac{61}{6}$

$\frac{67}{8} - \frac{61}{6} = \frac{-43}{24}$

Your $answer$ : $-1\frac{19}{24}$

Good luck on your assignment & enjoy your day

~ $MeIsKaitlyn :)$

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2 years ago

How do you find the HCF of 15t and 6s?

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3 years ago

Solve for z 4/z = 12/5 what is z

Verdich [7]

Answer:

5/3 = z

Step-by-step explanation:

You can use proportions to figure this out.

Imma solve this as I work through it.

4/z is equal to 12/5. So you can do something called the butterfly method (I have never used this before, but it works tho) and the method involves only multiplication and division.

Lemme clean this up for ya

The butterfly method involves multiplying in a cross format on both sides, so the

4 12

__ = ______

z 5

becomes 4 times 5, and z times 12.

4 times 5 is 20, and z times 12 is 12z

so you now have 20 = 12z

Lets simplify the equation by dividing by 4s

20 divided by 4 is 5 and 12z divided by 4 is 3z

5 = 3z

You can divide again

by dividing both sides

to get the unit rate of z.

It will be a fraction though

and it won't look pretty

but here it is:

__ = z

It is

5/3

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3 years ago

In a recent Super Bowl, a TV network predicted that 50 % of the audience would express an interest in seeing one of its forthcom

coldgirl [10]

Answer:

z= -0.968

We can conclude that we fail to reject the null hypothesis, and we can said that at 5% of significance the proportion of people who says that they would watch one of the television shows not differs from 0.5 or 50% .

Step-by-step explanation:

1) Data given and notation n

n=106 represent the random sample taken

X=48 represent the people who says that they would watch one of the television shows.

$\hat p=\frac{48}{106}=0.453$ estimated proportion of people who says that they would watch one of the television shows.

$p_o=0.5$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that 50% of people who says that they would watch one of the television shows.:

Null hypothesis: $p=0.5$

Alternative hypothesis: $p \neq 0.5$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.453 -0.5}{\sqrt{\frac{0.5(1-0.5)}{106}}}=-0.968$

4) Statistical decision

P value method or p value approach . "This method consists on determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level is not provided, but we can assume $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z$

So based on the p value obtained and using the significance level assumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we fail to reject the null hypothesis, and we can said that at 5% of significance the proportion of people who says that they would watch one of the television shows not differs from 0.5 or 50% .

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