Vertex at the origin and opening down → y=ax^2
Width: w=16
x=w/2→x=16/2→x=8
x=8, y=-16→y=ax^2→-16=a(8)^2→-16=a(64)→-16/64=a(64)/64→-1/4=a→a=-1/4
y=ax^2→y=-(1/4)x^2
7 m from the edge of the tunnel → x=w/2-7=8 m-7 m→x=1 m
x=1→y=-(1/4)x^2=-(1/4)(1)^2=-(1/4)(1)→y=-1/4
Vertical clearance: 16-1/4=16-0.25→Vertical clearance=15.75 m
Please, see the attached file.
Answer: Third option 15.75 m
D. x+ 40 = 150 this is the answer
9514 1404 393
Answer:
28 square units
Step-by-step explanation:
The rectangle is 7-0 = 7 units high and 6-2 = 4 units wide. Its area is the product of these dimensions:
A = LW
A = (7)(4) = 28 . . . square units
Answer:
There is no picture.
Step-by-step explanation: