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3 years ago

9

If your good at geometry come here. I need your help and if you could help me out successfully I will give you BRAINLIEST and PO

INTS.

1 answer:

larisa86 [58]3 years ago

8 0

Answer:

whats ur question

Step-by-step explanation:

(Ill still accept brainliest)

:) ☺️

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Ryan drove for 4.5 hours to his uncle’s house. His uncle lives 234 miles away. Assuming Ryan drove at a constant rate, at what s

Fantom [35]

If you were to find the constant rate, you would have to take 4.5 and divide it into 234 to get the answer

You would get 52 as the constant speed

5 0

3 years ago

Read 2 more answers

P(A)* P(B)≠ p(AnB)<br><br> Why does it contain a not equal to sign

RoseWind [281]

Answer:

P(A|D) and P(D|A) from the table above are not equal because P(A|D) = and P(D|A) =

Step-by-step explanation:

Conditional probability is the probability of one event occurring with some relationship to one or more other events

.

P(A|D) is called the "Conditional Probability" of A given D

P(D|A) is called the "Conditional Probability" of D given A

The formula for conditional probability of P(A|D) = P(D∩A)/P(D)

The formula for conditional probability of P(D|A) = P(A∩D)/P(A)

The table

↓ ↓ ↓

: C : D : Total

→ A : 6 : 2 : 8

→ B : 1 : 8 : 9

→Total : 7 : 10 : 17

∵ P(A|D) = P(D∩A)/P(D)

∵ P(D∩A) = 2 ⇒ the common of D and A

- P(D) means total of column D

∵ P(D) = 10

∴ P(A|D) =

∵ P(D|A) = P(A∩D)/P(A)

∵ P(A∩D) = 2 ⇒ the common of A and D

- P(A) means total of row A

∵ P(A) = 8

∴ P(D|A) =

∵ P(A|D) =

∵ P(D|A) =

∵ ≠

∴ P(A|D) and P(D|A) from the table above are not equal

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

True or false? The graph represents a function<br> 5<br> -5<br> A True<br> B. False

Daniel [21]

Answer:

True

Step-by-step explanation:

It passes the vertical line test, meaning you can draw a vertical line anywhere on the graph and it will only intersect at one point

this means that for every input (x value) there is only one output (y value)

6 0

2 years ago

Mr. and Mrs. Chan want to buy new furniture that has a cash price of $6230. On the installment plan, they must pay %25 of the ca

DENIUS [597]

The interest due on financing option is $307.50

What is interest on financing?

Interest on financing is the extra amount paid by the couple when their total payments are compared to the cash price of $6,230.

The total payments would be the 25% down payment plus the sum of the twelve monthly payments of $415 each

Down payment=cash price*25%

Down payment=$6230*25%

Down payment=$1,557.50

Total monthly payments=amount of each monthly payment*number of monthly payments

monthly payment=$415

number of monthly payments=12

Total monthly payments=$415*12

Total monthly payments=$4,980

Total payment under financing=Down payment +Total monthly payments

Total payment under financing=$1,557.50+$4,980

Total payment under financing=$6,537.50

Interest=$6,537.50-$6,230

Interest on financing=$307.50

Find out more on down payment on:brainly.com/question/1698287.

#SPJ1

7 0

1 year ago

Let V be the volume of the solid obtained by rotating about the y-axis the region bounded by y=√x and y=x^2. Find V either by sl

Ede4ka [16]

Answer:

The volume of the solid is $3\pi/10$

Step-by-step explanation:

In this case, the washer method seems to be easier and thus, it is the one I will use.

Since the rotation is around the y-axis we need to change de dependency of our variables to have $f(x)\rightarrow f(y)$ . Thus, our functions with $y$ as independent variable are:

$x=\sqrt{y}\\ x=y^2$

For the washer method, we need to find the area function, which is given by:

$A=\pi\cdot [(\rm{outer\ radius)^2 -(\rm{inner\ radius)^2 ]$

By taking a look at the plot I attached, one can easily see that for a rotation around the y-axis the outer radius is given by the function $x=\sqrt{y}$ and the inner one by $x=y^2$ . Thus, the area function is:

$A(y)=\pi\cdot [(\sqrt{y} )^2-(y^2)^2]\\A(y)=\pi\cdot (y-y^4)$

Now we just need to integrate. The integration limits are easy to find by just solving the equation $\sqrt(y)=y^2$ , which has two solutions $y=0$ and $y=1$ . These are then, our integration limits.

$V=\pi\int_{0}^1 (y-y^4)dy\\ V=\pi (\int_{0}^1 ydy - \int_{0}^1 y^4dy)\\ V=\pi/2-\pi/5\\\boxed{V=3\pi/10}$

3 0

3 years ago