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Andrews [41]
2 years ago
15

For which set of values is y a function of x? x у -1 6 0 8 1 1 10 2 12 ​

Mathematics
1 answer:
vodka [1.7K]2 years ago
4 0

Answer:

Step-by-step explanation

umm this not even real bro

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What is the format of this proof?
elena55 [62]
Divide b from both sides then it should be a equal C therefore if you add be it be the midpoint of a and C because BNB or equal to a C
4 0
3 years ago
Three numbers multiplied together give an answer of -12. The sum of two of the numbers is zero. What could the three numbers be?
Angelina_Jolie [31]
-2,2,3 since 2*-2*4 = 12 and -2+2=0
3 0
2 years ago
Help pleaseeeeeeeeeeeeee!!!!!!!!!!!!!!!! T^T
artcher [175]
1 + (-5/8) = 3/8

Explanation: If the coffee wasn’t drank it would’ve been at fraction 1 (or 100%)

Since he drank 5/8 of it. The coffee left is now 1-(5/8)

But since the question has asked to give the equation in addition format. Put a plus sign in between the two.

Therefore,
1 + (-5/8)

Solve it,
= 1-(5/8)
= (8-5)/8
= 3/8

Hence the equation is:

1 + (-5/8) = 3/8.
8 0
3 years ago
Read 2 more answers
Factor. 2xy+5x−12y−30
worty [1.4K]
2xy + 5x -12y -30
x(2y + 5)  - 6( 2y + 5)
(2y+5) (x-6)
5 0
3 years ago
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Given $dc = 7$, $cb = 8$, $ab = \frac{1}{4}ad$, and $ed = \frac{4}{5}ad$, find $fc$. Express your answer as a decimal.
Pachacha [2.7K]

A ↔ B ↔ C ↔ D ↔ E ↔ F

 \frac{1}{4} AD      8      7      \frac{4}{5} AD   ???

AB + BC + CD = AD   <em>segment addition postulate</em>

\frac{1}{4} AD   +   8   +   7   = AD

\frac{1}{4} AD   +       15        = AD

AD         + 60    = 4AD

                  60    = 3AD

                  20    = AD

AB =  \frac{1}{4} AD    =  \frac{1}{4}(20)    = 5

DE =  \frac{4}{5}AD   =  \frac{4}{5}(5)    = 4

CD + DE + EF = CF   <em>segment addition postulate</em>

7   +   4   + EF  = CF

     11        + EF  = CF

Answer: 11 + EF

Note: You did not provide any info about EF.  If you have additional information that you did not type in, calculate EF and add it to 11 to find the length of CF.

7 0
3 years ago
Read 2 more answers
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