Answer:
5r^2+2
Step-by-step explanation:
(4r^2 – 3r + 2) – (-r^2 – 3r) =
Distribute the minus sign
(4r^2 – 3r + 2) +r^2 + 3r =
Combine like terms
(4r^2 + r^2 – 3r+ 3r + 2) =
5r^2+2
C . no solution , that’s what I think :)
H(t) = Ho +Vot - gt^2/2
Vo = 19.6 m/s
Ho = 58.8 m
g = 9.8 m/s^2
H(t) = 58.8 + 19.6t -9.8t^2/2 = 58.8 + 19.6t - 4.9t^2
Maximun height is at the vertex of the parabole
To find the vertex, first find the roots.
58.8 + 19.6t - 4.9t^2 = 0
Divide by 4.9
12 + 4t - t^2 = 0
Change sign and reorder
t^2 - 4t -12 = 0
Factor
(t - 6)(t + 2) =0 ==> t = 6 and t = -2.
The vertex is in the mid point between both roots
Find H(t) for: t = [6 - 2]/2 =4/2 = 2
Find H(t) for t = 2
H(6) = 58.8 + 19.6(2) - 4.9(2)^2 = 78.4
Answer: the maximum height is 78.4 m
Answer:
C. x = 15 * sin 18°
Step-by-step explanation:
sin A = Opposite / Hypotenuse
sin 18° = x / 15
x = 15 * sin 18°
8.9 x 10^-5 in scientific notation
