Answer:
the fourth answer is correct
3(8+3)
You distribute the 3 to the 8 to get 24 and the 3 to the other 3 to get 9, which then equals 24+9, which was the original problem
Answer:
8y = - 6
Step-by-step explanation:
Given the 2 equations
x + 6y = 9 → (1)
- x + 2y = - 15 → (2)
Adding the 2 equations term by term gives
(x - x) + (6y + 2y) = (9 - 15), that is
8y = - 6
Answer: 3|x| = 3x when x 
0 and 3|x| = -3x when x < 0
Step-by-step explanation: Absolute value basically refers to the distance of a point from the origin (zero), regardless of the direction. The absolute value of a number is represented by two vertical lines enclosing the number. For example, |6| = 6, or in this case, 3|x| = 3x. Here, the value is replaced by the term "x". "x" is used as a term for an unknown value/variable. so basically, we're solving for x kinda. Multiplying "x" (the unknown variable) by 3 gives us = 3x. We know from the sign that x <u>can't be below zero</u>, only <u>above or equal to</u>. So, 3lxl = 3x when x is above or equal to the origin (zero). We know from the second problem that x <u>can't be above zero </u>because of the sign <, only <u>below zero</u>. Because we can only go below zero, that positive 3 turns negative. Multiplying x by -3 gives us = -3x. So, 3|x| = -3x when x is blow the origin (zero).
Note: <u>the absolute value of a number is always positive</u>, but in this scenario this rule doesn't apply because "x" is not a number, only a unknown value.
Sorry in advance if my explanation still doesn't make sense. Math isn't my thing really.
The midpoint of the segment shown below is (1, -3/2). Option A) is the correct answer.
<u>Step-by-step explanation</u>:
The two end points of the line segments are (1,2) and (1,-5).
<u>step 1</u> :
Midpoint formula = ((x1 + x2)/2 , (y1 +y 2)/2)
<u>step 2</u> :
(x1, y1) = (1, 2)
(x2, y2) = (1, -5)
<u>step 3</u> :
Substitute the values in the midpoint formula,
Midpoint = ((1 + 1)/2 , (2 -5)/2)
= ((2/2) , (-3/2))
= (1, -3/2)
Answer:print("PARES E IMPARES") numero_1 = int(input("Escriba un número entero: ... del programa realiza un bucle desde el primer número introducido al segundo. ... iteración si la variable de control i es par o no (comprobando si el resto de la ... Tras calcular la suma, el programa tiene que escribir la expresión algebraica
Step-by-step explanation:
