Simply combining like terms:21b-32+7b-20b
1 answer:
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Answer:
Step-by-step explanation:
We are given the polynomial and we are dividing by (x+3). So by performing one step of synthetic division we get
1 2 -2 3|-3
-3 3 -3
1 -1 1 0
So the quotient in polynomial form is
Option A : 25° C
Option C : -43° C
Option E : 0° C
Explanation:
It is given that the Methanol is in liquid form if its temperature is between -93.9°C and 64.96°C.
Let x represents the Methanol's temperature. Writing the temperature in interval notation, we have,
Now, let us determine from the given options that the temperatures at what are all the temperatures the methanol will be in liquid form.
Option A: 25° C
It is obvious that the 25° C lies in the interval
Hence, at 25° C Methanol will be in liquid form.
Thus, Option A is the correct answer.
Option B: -95° C
We can see that the temperature -95° C does not lie in the interval
Hence, at -95° C Methanol will not be in liquid form.
Thus, Option B is not the correct answer.
Option C: -43° C
We can see that the temperature -43° C lies in the interval
Hence, at -43° C Methanol will be in liquid form.
Thus, Option C is the correct answer.
Option D: 67° C
We can see that the temperature 67° C does not lie in the interval
Hence, at 67° C Methanol will not be in liquid form.
Thus, Option D is not the correct answer.
Option E: 0° C
We can see that the temperature 0° C lies in the interval
Hence, at 0° C Methanol will be in liquid form.
Thus, Option E is the correct answer.
Option F: 89° C
We can see that the temperature 89° C does not lie in the interval
Hence, at 89° C Methanol will not be in liquid form.
Thus, Option F is not the correct answer.