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eimsori [14]
3 years ago
9

Find the perimeter of the larger pentagon if the two pentagons are similar.

Mathematics
1 answer:
Kruka [31]3 years ago
3 0

The two pentagons are similar, so we know corresponding sides will all be in the ratio 24/18
 for example the vertical right side can be found by:
  24/18=x/21 x=28.
  Find the other sides similarly and add them all up.

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The drop box options:<br> &lt;<br> &gt;<br> Please I need help:(
guajiro [1.7K]

Answer:

c+2<1

on the number line, c is like -1.1 and 2-1.1 is .9 and .9>1

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7 0
3 years ago
What is the measure of the missing angle?​
Degger [83]

Answer:

115

Step-by-step explanation:

3 0
4 years ago
Solve for v . =−16 − 47v
Schach [20]
I'm pretty sure this is what you have to do;
v=-16-47v
add 47v on the other side of the equal sign
47v=-16
then divide 47 on each side of the equal sign
47v÷47v=1v or just v
-16÷47=-0.3
v=-0.3
I think this is right.
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5 0
3 years ago
A bag contains 9 marbles: 2 are green, 3 are red, and 4 are blue. Raina chooses a marble at random, and without putting it back,
Yakvenalex [24]
<h3>Answer:   1/12</h3>

=========================================================

Explanation:

There are 3 red out of 9 total

The probability of picking red at random is 3/9 = 1/3

If the first marble is not put back, then the chances of picking red again are now 2/8 = 1/4

Notice how I subtracted 1 from the numerator and denominator of 3/9 to get to 2/8. This is because the red count and the total count both go down by 1 each.

Now multiply the fractions mentioned:

(3/9)*(2/8) = (1/3)*(1/4) = (1*1)/(3*4) = 1/12

If you did this trial 12 times, then you should expect to get two reds about once. That's one way to interpret the probability of 1/12.

Side note: 1/12 = 0.0833 = 8.33% approximately

5 0
2 years ago
The running back for the Bulldogs football team carried the ball 5 times for a total loss of 8 3 4 yards. Find the average chang
aliya0001 [1]

Answer: The average change in field position on each run was 1\frac34 yards.

Step-by-step explanation:

Given: Total loss of field = 8\dfrac34 yards  = \dfrac{35}{5}\text{ yards}

Number of times football team carried the ball  = 5

The average change in field position on each run =  \dfrac{\frac{35}{4}}{5}

=\dfrac{35}{4\times5}\\\\=\dfrac{7}{4}\\\\=1\dfrac34 yard .

The average change in field position on each run was 1\frac34 yards.

4 0
3 years ago
Read 2 more answers
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