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irina1246 [14]
2 years ago
15

Add me as your friend

Mathematics
2 answers:
natka813 [3]2 years ago
3 0

Answer:

no thank you

Step-by-step explanation:

Lady_Fox [76]2 years ago
3 0

Answer:

Sure why not:))))

Step-by-step explanation:

So like my word have to be 20 character long

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An engineer is comparing voltages for two types of batteries (K and Q) using a sample of 37 type K batteries and a sample of 58
Olegator [25]

Answer:

Hypothesis Test states that we will accept null hypothesis.

Step-by-step explanation:

We are given that an engineer is comparing voltages for two types of batteries (K and Q).

where, \mu_1 = true mean voltage for type K batteries.

           \mu_2 = true mean voltage for type Q batteries.

So, Null Hypothesis, H_0 :  \mu_1 = \mu_2 {mean voltage for these two types of

                                                        batteries is same}

Alternate Hypothesis, H_1 : \mu_1 \neq \mu_2 {mean voltage for these two types of

                                                          batteries is different]

<em>The test statistics we use here will be :</em>

                     \frac{(X_1bar-X_2bar) - (\mu_1 - \mu_2) }{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}  } }  follows t_n__1 + n_2  -2

where, X_1bar = 8.54         and     X_2bar = 8.69

                s_1  = 0.225       and         s_2     =  0.725

               n_1   =  37           and         n_2     =  58

               s_p = \sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2}  }{n_1+n_2-2} } =   \sqrt{\frac{(37-1)0.225^{2}+(58-1)0.725^{2}  }{37+58-2} }  =  0.585               Here, we use t test statistics because we know nothing about population standard deviations.

     Test statistics =  \frac{(8.54-8.69) - 0 }{0.585\sqrt{\frac{1}{37}+\frac{1}{58}  } } follows t_9_3

                             = -1.219

<em>At 0.1 or 10% level of significance t table gives a critical value between (-1.671,-1.658) to (1.671,1.658) at 93 degree of freedom. Since our test statistics is more than the critical table value of t as -1.219 > (-1.671,-1.658) so we have insufficient evidence to reject null hypothesis.</em>

Therefore, we conclude that mean voltage for these two types of batteries is same.

6 0
3 years ago
X/4 - y/3 =1 X and Y axis standard form
Semenov [28]

Answer:

Step-by-step explanation:

x/4 - y/3 = 1..multiply everything by the LCD....which is 12

3x - 4y = 12 <== standard form

=====================================

if it makes it easier for u, x/4 is the same as (1/4)x and y/3 is the same as (1/3)y

so ur problem can be written as : (1/4)x - (1/3)y = 1....multiply by 12

12(1/4)x - 12(1/3)y = 12(1)

(12/4)x - (12/3)y = 12.....reduce

3x - 4y = 12

5 0
3 years ago
Please help me solve this short problem guys
-BARSIC- [3]

Answer:

Step-by-step explanation:

Given equation of the quadratic function is,

y = x² + 5x - 7

Convert this equation into vertex form,

y = x² + 2(2.5x) - 7

  = x² + 2(2.5x) + (2.5)² - (2.5)² - 7

  = (x + 2.5)²- 6.25 - 7

  = (x + 2.5)² - 13.25

Therefore, vertex of the function is → (-2.5, -13.25)

For the solutions,

y = 0

(x + 2.5)² - 13.25 = 0

x = (±√13.25) - 2.5

x = (±3.64) - 2.5

x = 1.14, -6.14

Solutions → (-6.14, 0) and (1.14, 0)

8 0
2 years ago
Given that f(x)=2x/3 evaluate f^-1(6)
abruzzese [7]

Answer:

9

Step-by-step explanation:

we know by definition that

f^{-1}(f(x))=x\\\\f^{-1}(\frac{2x}{3})=x\\\\f^{-1}(x)=ax\\\\f^{-1}(\frac{2x}{3})=a(\frac{2x}{3})=x\\\\f^{-1}(x)=\frac{3x}{2}

so now we evaluate

f^{-1}(6)=\frac{3*6}{2}\\\\=3*3\\\\f^{-1}(6)=9

and if we want to do an extra step

f^{-1}(f(6))=6\\\\f^{-1}(\frac{2*6}{3})=f^{-1}(4)=\frac{3*4}{2}=6

which works.

4 0
2 years ago
Solve the equation and enter the value of x below.<br> x + 29 = 49<br> X =
andrew-mc [135]

Answer:

x = 20

Step-by-step explanation:

x + 29 = 49

- 29       - 29

x=20

5 0
2 years ago
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