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Ksivusya [100]
3 years ago
15

An area of 18 square feet that is 6 feet long and 3 feet wide. A rug covered 1/3 square foot tiles. How many tiles will the rug

cover? Write an equation
Mathematics
2 answers:
Shkiper50 [21]3 years ago
5 0

Answer:

The number of tiles the rug will cover is 54 tiles

Step-by-step explanation:

Here we have,

Total area covered by the rug = 18 ft²

Size of one tile = 1/3 ft²

Therefore the number of tiles that can fit into the the area is given by;

Total area of the rug ÷ Area of one tile

= 18 ft² ÷ 1/3 ft²

Here we note that we are dividing a number by a fraction which is the same as multiplying the number by the inverse of the fraction as follows

= 18 × 3/1 ft²/ft² = 54 tiles

The number of tiles the rug will cover = 54 tiles.

Helga [31]3 years ago
4 0

Answer:

  • 54 tiles
  • Y = X / 3

Step-by-step explanation:

Area of Room = 18 ft^2

length of Room = 6 ft

width of Room = 3 ft

size of tiles = 1/3 ft^2

How many tiles is needed to cover 18 ft^2

= 18 ft ^2 / size of each tile

= 18 ft^2 / 1/3 ft^2

= 18 * 3 = 54 tiles

lets assume Area of rug needed  = Y

number of tiles = x

therefore Y = X / 3 equation

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set them equal to each other

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x=0


x-1=0

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subsitute back to find y values

y=x+1, y=0+1, y=1, one point is (0,1)

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the 2 points of intersection are (0,1) and (1,2)

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4 years ago
a store sells new DVDs for $12 each. used DVDs sell for $7 each. Joseph is buying two new DVDs and X used DVDs. write an equatio
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3 years ago
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An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y
aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                               P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average time = 23.92 minutes

             s = sample standard deviation = 6.72 minutes

             n = sample of times = 40

             \mu = population mean assembly time

<em> Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

<u>So, a 98% confidence interval for the population mean, </u>\mu<u> is; </u>

P(-2.426 < t_3_9 < 2.426) = 0.98  {As the critical value of z at 1%  level

                                               of significance are -2.426 & 2.426}  

P(-2.426 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.426) = 0.98

P( -2.426 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

P( \bar X-2.426 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

<u>98% confidence interval for</u> \mu = [ \bar X-2.426 \times {\frac{s}{\sqrt{n} } } , \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ]

                                     = [ 23.92-2.426 \times {\frac{6.72}{\sqrt{40} } } , 23.92+2.426 \times {\frac{6.72}{\sqrt{40} } } ]  

                                    = [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0
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Answer:

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Step-by-step explanation:

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