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3 years ago

What is 0.267 rounded off to 1 significant figure

Mathematics

2 answers:

Anuta_ua [19.1K]3 years ago

5 0

The answer is 0.3

Do you want me to explain?

devlian [24]3 years ago

5 0

0.3 is the answer hope this helps:)

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Find the geometric mean of 6 and 96.

adelina 88 [10]

<span>The geometric mean of 6 and 96 = sqrt(6 * 96) = sqrt(576) = 24</span>

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3 years ago

Reduce any fractions to lowest terms.Don’t round your answer, and don’t use mixed fractions

DENIUS [597]

Answer:

t < $\frac{38}{17}$

Step-by-step explanation:

Add '5t' to both sides

12t - 2 +5t < -5t +36 +5t

17t -2 < 36

Add ' 2' to both sides

17t -2 +2 < 36 + 2

17t < 38

Dividing '17' on both sides

$\frac{17t}{17}$ < $\frac{38}{17}$

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3 years ago

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An automobile manufacturer has given its car a 52.6 miles/gallon (MPG) rating. An independent testing firm has been contracted t

Arte-miy333 [17]

Answer:

Null hypothesis: $\mu = 52.6$

Alternative hypothesis: $\mu \neq 52.6$

$z=\frac{52.8-52.6}{\frac{1.6}{\sqrt{250}}}=1.976$

$p_v =2*P(z>1.976)=0.0482$

Since the p value is lower than the significance level wedon't have enough evidence to conclude that the true mean is significantly different from 52.6 MPG.

Step-by-step explanation:

Information provided

$\bar X=52.8$ represent the sample mean for the MPG of the cars

$\sigma=1.6$ represent the population standard deviation

$n=250$ sample size of cars

$\mu_o =52.6$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test

Hypothesis

We need to conduct a hypothesis in order to check if the true mean of MPG is different from 52.6 MPG, the system of hypothesis would be:

Null hypothesis: $\mu = 52.6$

Alternative hypothesis: $\mu \neq 52.6$

Since we know the population deviation the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

Calculate the statistic

Replacing we have this:

$z=\frac{52.8-52.6}{\frac{1.6}{\sqrt{250}}}=1.976$

Decision

Since is a two tailed test the p value would be:

$p_v =2*P(z>1.976)=0.0482$

Since the p value is lower than the significance level wedon't have enough evidence to conclude that the true mean is significantly different from 52.6 MPG.

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3 years ago

Match each statement (term) with its value in relation to 0 (definition). NEED THIS ASAP

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Answer:

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I took the test so hope this helps you :)

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