3 years ago

If you flipped a fair coin 18 times, about how many times would you expect heads to appear? HELP ME PLEASE!!!!!!!

Mathematics

1 answer:

Andrei [34K]3 years ago

4 0

Answer:

9 or 3.8x10^-6

Step-by-step explanation:

By flipping a coin you'd look at how many times a head could appear (1/2) and multiply that by the 18 times.

Another explanation:

I'm not sure on this but would you raise 1/2 to the 18th power?

You might be interested in

A family has two cars during one particular week the first car consumed 25 gallons of gas and the second consumed 40 gallons of

Ede4ka [16]

Answer:

Step-by-step explanation:

Ffgjjnmmmnn

8 0

3 years ago

What is the answer to #3?

omeli [17]

Letter D is probably the right answer

3 0

3 years ago

Can some help me i don't understand how to do this math!!

Natasha_Volkova [10]

Answer:

Step-by-step explanation:

$\frac{x}{(x-2)^{2} } -\frac{x}{(x-2)(x-1)} = \frac{x^{2}-x-x^{2} +2x }{(x-2)^{2}(x-1) }$

? = 2x -x = x

6 0

2 years ago

Use the zero x = 5, to help find the remaining zeros of x4 - 4x3 - 14x² + 36x + 45. Select one:

zepelin [54]

Answer:

huh

Step-by-step explanation:

5 0

2 years ago

How do you do this problem???????????????/

AlekseyPX

Answer:

Price in Japan= 17.81

Price in Switzerland = 13.58

Step-by-step explanation:

First set up system of equations

80.59 = 3j +2s

76.36 = 2j + 3s

Make it to where you can eliminate one variable

161.18 = 6j +4 s

-229.08 = -6j - 9s

Reset the problem

-67.9 = -5s

s=13.58

Re plug them in to the original equation to get j = 17.81

7 0

3 years ago