Answer:
The volume of air in buoy is 3.05 cubic meters.
Step-by-step explanation:
We are given the following in the question:
Diameter = 1.8 meters
Radius, r =
The radius of buoy is 0.9 meters.
Volume of air in buoy:
Volume of sphere =
Thus, the volume of air in buoy is 3.05 cubic meters.
A) f(x) = x - 4 , g(x) = x + 4
⇒ f( g(x) ) = x + 4 - 4 = x
g( f(x) ) = x - 4 + 4 = x
⇒ f and g are not inverses of each other
b) f(x) = -1/(3x) , x ≠ 0 ; g(x) = 1/(3x) , x ≠ 0
⇒ f( g(x) ) = -1/( 3*(1/(3x)) ) = -1/(1/x) = -x
g (f(x) ) = 1/( 3*(-1/(3x)) ) = 1/( -1/x) = -x
⇒ f and g <span>are not inverses of each other</span>
The circle the has a center P(2,0) is bigger than compared to the circle with the center Q(0,4) because the former has a radius 20, while the latter has a radius of only 2. You can view the graph here:
https://www.desmos.com/calculator/od1pwqylou
(a) Describe the rule for translating center Q onto center P. By moving the center of circle Q overlapping the center of circle P, then we need to move it two units left and 4 units up.
(b) Determine the scale factor for dilating circle Q so that it has the same radius as circle P. In getting the scale factor, we need to compare the radius
= 2/10
= 1/10
So, the scale factor is 1/10
(c) Are circles P and Q similar? Explain your answer.
Yes, by applying a dilation value, circle Q can be transformed to circle P, vice versa.
28 or 28.0 or how many gratuitous zeros you want.
Answer:
(140, 200)
Step-by-step explanation:
The coordinate points are (140, 200), the x axis is over 140 and the y axis is up 200.
