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givi [52]
3 years ago
14

Can anyone help? very confusing and please show work :)

Mathematics
2 answers:
Yakvenalex [24]3 years ago
8 0
5 is very easy. the transverse cuts at a 90 degree angle, so your equation will look like this
21x+6=90
to find x, you have to work it out using this equation
start by negating the sign and finding out what the sum and equation was before 6 was added.
21x+6=90
-6 -6
21x=84
next, you have to divide both sides by 21 to get the variable (x) to stand alone
(21x)/21=(84)/21
x=4
(use this formula to find number 6!!)

all of the missing angle measurements are 90 degrees. to find this, you have to remember that a straight line is always a 180 degree angle. so, if you have a transversal with only one given angle, you simply subtract 180 from the given angle.
in number 5, it would look like this
180-90=90
these formulas are used for both questions. if you need further help, let me know!
DerKrebs [107]3 years ago
5 0
The first one:
21x+6=90
21x=84
x=4

The second one:
11x-2=75
11x=77
x=7

Hope this helps :)
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<em>We'd solve anything inside the parentheses first:</em>

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Answer:

Building's shadow length = 180 feet.

Step-by-step explanation:

Given:

A 50-foot flagpole is at the entrance of a building that is 300 feet tall.

Its forms a right angled triangle from both ends,both of them are similar because the angle of the sun is the same at the same time of day.

From similar triangle property we can say that.

⇒ length of the building shadow times height of the flagpole's = length of the flagpole's shadow times height of the building

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\frac{length\ of\ the\ building\ shadow}{height\ of\ the\ building} =\frac{length\of\ the\ flagpole's\ shadow}{height\ of\ the\ flagpole's}

Plugging the values in the above equation we have,

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⇒ \frac{x}{300}\times 300 =\frac{30}{50}\times 300

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In triangle ABC, m∠A = 36°, m∠B = 84°, and m∠C = 60°. The side lengths, in order from greatest to least, are , , .
katen-ka-za [31]

In the triangle ABC, the side lengths, in order from the greatest to the least, are : AC > AB > BC.

We are given a triangle. The vertices of the triangle are A, B, and C. The measures of the angles ∠A, ∠B, and ∠C are 36°, 84°, and 60°, respectively. We need to arrange the side lengths in order from the greatest to the least.

The side lengths are proportional to their opposing angles in a triangle. It means that the side opposite the largest angle is the largest side, and vice versa. The angles arranged in descending order are : 84° > 60° > 36°. The angles arranged in descending order according to the vertices are : B > C > A. The order of the lengths of the opposite sides must be the same.

Hence, the side lengths, in order from the greatest to the least, are : AC > AB > BC.

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brainly.com/question/2773823

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