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WITCHER [35]
2 years ago
8

The area of a square patio is 225 square feet. What is the perimeter of the patio

Mathematics
1 answer:
Elanso [62]2 years ago
5 0
STEP 1:
find the length of the sides of the square

AREA FORMULA (for a square)
x= side

A=x^2

225=x^2
take square root of both sides

15 feet= x


STEP 2:
find perimeter

PERIMETER FORMULA (for a square)

x= side of square

P= 4x
use x value from step 1

P= 4(15 ft)
P= 60 feet


ANSWER: The perimeter is 60 feet.

Hope this helps! :)
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If you roll a six-sided dice, what is the probability of rolling an odd number?
fomenos

Step-by-step explanation:

A six sided dice contains even numbers on three sides and odd numbers on remaining three sides.

Therefore,

Probability of rolling an odd number

=  \frac{3}{6}  \\ \\   =  \frac{1}{2}

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3 years ago
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andre [41]
Simplify the equation.

First, distribute the 2 in the left side of the equation.
Resulting in: 2x-6 = (x-1) + 7

Second, remove the parentheses form the right side of the equation (there is nothing to distribute there).
Resulting in: x - 1 + 7

Now simplify the right side of the equation by subtracting the 1 from the 7.
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Our goal is to isolate the x to the left side, and the numerals to the right side.
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Lastly, in order to fully isolate the variable (x), we divide both sides by 2.
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3 years ago
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According to the University of Nevada Center for Logistics Management, 6% of all mer-
Fudgin [204]

Answer:

a) The point estimate of the proportion of items returned for the population of

sales transactions at the Houston store = 12/80 = 0.15

b) The 95% confidence interval for the proportion of returns at the Houston store = [0.0718 < p < 0.2282].

c) Yes.

We set an hypothesis and construct a test statistics. The test statistics result gives us:

Z calculated  = 2.2545, and this gives us the p-value = 0.0121. We assumed 95% confident interval. Hence, the level of significance (α) = 5%. Conclusively, since the p-value ==> 0.0121 is less than (α) = 5%, the test is significant. Hence, the proportion of returns at the Houston store is significantly different from the returns  for the nation as a whole.

Step-by-step explanation:

a) Point estimate of the proportion = number of returned items/ total items sold = 12/80 = 0.15.

b) By formula of confident interval:

CI(95%) = p ± Z*\sqrt{\frac{p*(1-p)}{n} }  =  0.15 \pm 1.96 *\sqrt{\frac{0.15*(1-0.15)}{80} },

CI(95%) = [0.0718 < p < 0.2282]

c) The hypothesis:

H_{0}: The proportion of returns at the Houston store is not significantly different from the returns  for the nation as a whole.

H_{a}: The proportion of returns at the Houston store is significantly different from the returns  for the nation as a whole.

The test statistics:

Z = \frac{\hat{p} - p_{0}}{\sqrt{\frac{p*(1-p)}{n} }}, where p_{0} is the proportion of nation returns.

Z calculated  = 2.2545, and this gives us the p-value = 0.0121. We assumed 95% confident interval. Hence, the level of significance (α) = 5%. Conclusively, since the p-value ==> 0.0121 is less than (α) = 5%, the test is significant. Hence, the proportion of returns at the Houston store is significantly different from the returns  for the nation as a whole.

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