Answer:
Step-by-step explanation:
Given that g is a function from g : {1, 2, 3} ->{1, 2, 4, 8}
by the function
i.e. we have
Range = {2,4,8} Since there is an extra element 1 in the co domain which is not in range , g is not on to
But g is one to one as 1,2,3 have different images.
This is a trick question. First just understand that any number over itself is 1 so
is just
so it is just
2
If you have a graph, I’d use it and make curved lines going down to plot the points!
Using -17 ,15
And, 15 , -13
Hope this helps!
Use the internet that is what i would sorry i am in the 10th grade
Answer:
5
Step-by-step explanation:
For an equation to be dimensionally correct the dimension of quantities on both sides of equation must be same.
Also, two physically quantities can only be added or subtracted only when their dimension are same.
here all option are dimensionally correct except the 5th option where
dimension of t= [T] whereas dimension of a/v is
= T^{-1}
since, the dimension of quantities on either sides of equation are not the same the equation is dimensionally is incorrect.