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EastWind [94]
3 years ago
14

Given f(x)=-5x-4solve for when f(x)=1

Mathematics
2 answers:
olganol [36]3 years ago
4 0

Answer:

1

Step-by-step explanation:

f(x)=5x-4                   f(x)=1

1=5x-4

1+4=5x

5=5x

x=1

Zina [86]3 years ago
4 0

Answer:

f(x)=-9

Step-by-step explanation:

f(x)=-5x-4 solve for when f(x)=1

substitute x with 1

f(x)=-5-4

f(x)=-9

You might be interested in
Given X(4, -7). What are the coordinates of X" if
Vika [28.1K]
<h3>Answer:</h3>

B. (0, 9)

<h3>Step-by-step explanation:</h3>

Reflection across x=a is represented by the transformation ...

... (x, y) ⇒(2a-x, y)

Reflection across y=b is represented by the transformation ...

... (x, y) ⇒ (x, 2b-y)

The double reflection, across x=2, y=1 will result in the transformation ...

... (x, y) ⇒ (2·2-x, y) ⇒ (4-x, 2·1-y) ⇒ (4-x, 2-y)

For (x, y) = X(4, -7), the transformed point is ...

... X''(4-4, 2-(-7)) = X''(0, 9)

6 0
3 years ago
What is the standard form equation of the line shown below?
ch4aika [34]
(-1,1)(1,4)
slope = (4 - 1) / (1 - (-1) = 3/(1 + 1) = 3/2

y = mx + b
slope(m) = 3/2
use either of ur points....(1,4)...x = 1 and y = 4
now sub and find b, the y int
4 = 3/2(1) + b
4 = 3/2 + b
4 - 3/2 = b
8/2 - 3/2 = b
5/2 = b

equation is y = 3/2x + 5/2...but we need it in standard form

y = 3/2x + 5/2
-3/2x + y = 5/2.....multiply both sides by -2
3x - 2y = -5 <==== ur standard form equation
3 0
3 years ago
5. Find the value of x in each of the following.<br> 2/3=6/x. 4/7=x/21
nikitadnepr [17]
6/9 and 12/21
i think this is the answer your looking for
7 0
3 years ago
Alex’s printer can print 8 photos in 12 minutes.
nataly862011 [7]

Answer:

B and D

Step-by-step explanation:

7 0
3 years ago
3
iren2701 [21]

Answer:

B

D

A

Step-by-step explanation:

Given:

A. 2x^3-x^{2} -6x

B. 2x^3+8x+4

C. 3x^4+x^{2} +x-7

D. 3x^4-3x^{2} +5x-7

Now, let us evaluate the given expressions one by one.

(4x^3-4+ 7x)-(2x^3-x-8)\\\Rightarrow 4x^3-4+ 7x-2x^3+x+8\\\Rightarrow 2x^3+8x+ 4

It is equation B.

So, (4x^3-4+ 7x)-(2x^3-x-8) is equivalent to B.

(-3x^2+x^4+x)+(2x^4-7+4x)\\\Rightarrow -3x^2+x^4+x+2x^4-7+4x\\\Rightarrow3x^4-3x^{2} +5x-7

It is equation D.

So, (-3x^2+x^4+x)+(2x^4-7+4x)  is equivalent to D.

(x^{2} -2x)(2x+3)\\\Rightarrow 2x^3-4x^{2} +3x^{2} -6x\\\Rightarrow 2x^3-x^{2} -6x

It is equation A.

So, (x^{2} -2x)(2x+3) is equivalent to A.

So, answer is:

B

D

A

8 0
3 years ago
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