Answer:
Step-by-step explanation:
Given :
In the given quadrilateral ABCD,
BN and DM are the perpendiculars drawn to AC such that,
BN = DM
To prove:
Point O is the midpoint of segment BD.
Or
OD = OB
Solution:
In ΔOMD and ΔONB,
∠MOD ≅ NOB [Vertical angles]
∠M ≅ ∠N ≅ 90° [Given]
Therefore, by AA property of similarity,
ΔOMD ~ Δ ONB
Therefore, their corresponding sides will be proportional,
Since BN = DM,
OD = OB
Hence O is the midpoint of BD.