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jarptica [38.1K]
3 years ago
7

How to write 229,909 227,011

Mathematics
1 answer:
Alex787 [66]3 years ago
8 0

Answer:

two hundred twenty-nine billion nine hundred nine million two hundred twenty- seven thousand and eleven

Step-by-step explanation:

Include all the details i put down

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The length of a rectangle is 12 cm more than its width. Find the
just olya [345]

Dimensions of the rectangle (width and length) are 19 cm and 31 cm respectively.

Step-by-step explanation:

  • Step 1: Given that the perimeter = 100 cm, let width be x cm and then length = 12 + x.

Perimeter of a rectangle = 2(length + width)

100 = 2(x + 12 + x)

100 = 4x + 24

4x = 100 - 24 = 76

∴ x = 76/4 = 19 cm

∴ Length = 19 + 12 = 31 cm

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Solve for x: 4(x-2)+6=2(5x-6)
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4(x - 2) + 6 = 2(5x - 6)     <em>use distributive property</em>

(4)(x) + (4)(-2) + 6 = (2)(5x) + (2)(-6)

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4x = 10x - 10       <em>subtract 10 from both sides</em>

-6x = -10      <em>divide both sides by (-6)</em>

x = 10/6

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A 16 foot ladder rests against the side of a house and the base of the ladder is 4 feet away. How high above the ground is the t
PtichkaEL [24]

Answer:

  15.5 ft

Step-by-step explanation:

The geometry of the problem can be modeled by a right triangle with hypotenuse 16 ft and one side length of 4 ft. If x represents the height of the ladder on the building, then the Pythagorean theorem tells us ...

  x^2 + (4 ft)^2 = (16 ft)^2

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  x ≈ 15.5 ft . . . . . . . . . . take the square root

The top of the ladder is about 15.5 ft above the ground.

8 0
3 years ago
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