Answer:
1st Step: Observation
2nd Step: Questioning
3rd Step: Data Collection
4th Step: Data analysis
5th Step: Communication
In the scientific method, the first step is always to make an observation. You can observe anything in your environment, or a phenomena, or behavior.
The next step would be to question. You form a question to find a possible explanation as to why what you had observed occurred. This is also when you make a hypothesis. An educated guess or a proposal that could explain the event.
After you make a hypothesis, you start an experiment where you will collect data. The data you collect would then be analyzed (4th step). From there you build your conclusion to determine whether your hypothesis holds true.
The last step would be communication. You will communicate the results of your method. This allows people to review your data and process, which may be supported or invalidated. Communication is critical in the scientific world because your results could be the basis for further investigation.
Answer:
The statement '<em>the genetic material of the original cell is divided among the new cells</em>' describes how cells are produced in meiosis process.
<u>Explanation: </u>
<em>In meiosis a single cell is divided into twice to form four cells and it contains the original half amount of 'genetic information'.</em> In meiosis, the two cells are called daughter cells are produced, and each identical cells to the parent cell meiosis are produced four haploid cells and mitosis are produced two diploid cells.
<em>The meiosis cell division is to reduces the number of 'chromosomes' in the parent cell by its half portion and also they produce four gamete cells.</em> In this process they required to produce 'eggs and sperm' cells for the sexual reproduction .It is the main aim to make a daughter cells with same half so many 'chromosomes' as the starting cell.
Answer:
Uno de los progenitores es heterocigoto para color naranja (Nn) y el otro parental es homocigoto recesivo para gris (nn). Al haber una cruza entre un homocigoto recesivo y un heterocigoto, la 50% de la progenie expresa color naranja (Nn), mientras que el otro 50% expresa color gris (nn).
Explanation:
<u>Datos disponibles:</u>
- Cruce entre peces naranjas y peces grises
- 50% de la F1 son peces grises
- Naranja dominante sobre gris
Podemos nombrar el alelo dominante para color naranja <em>N</em>, y al alelo recesivo para color gris <em>n</em>.
Para que en un cruce entre dos fenotipos distintos, el 50% de la primer camada exprese uno de estos fenotipos, entonces uno de los parentales debe ser heterocigoto, mientras que el otro parental debe ser homocigoto recesivo. De esta forma 50% de la primera generación expresara uno de los fenotipos, mientras que el otro 50% expresará el otro fenotipo.
Supongamos que uno de los parentales lleva el genotipo <em>Nn</em>, y el otro parental es <em>nn</em>.
Cruce:
Parental) Nn x nn
Gametas) N n n n
Fenotipos) Naranja Gris
Cuadro de Punnett) N n
n Nn nn
n Nn nn
F1) 2/4 = 1/2 = 50% de la progenie tendrá genotipo heterocigoto, Nn
2/4 = 1/2 = 50% de la progenie tendrá genotipo homocigota recesivo,
nn
50% de la progenie será color naranja (Nn)
50% de la progenie será color gris (nn)
