Stem cell differentiation involves the changing of a cell to a more specialized cell type, involving a switch from proliferation to specialization. This involves a succession of alterations in cell morphology, membrane potential, metabolic activity and responsiveness to certain signals.
Answer:
True
Explanation:
The mRNA molecules are transported through the nuclear go into the cytoplasm, where they are translated by the rRNA of ribosomes
Answer:
CH3 + 2O2-----> CO2+2H2O
Na+ + Cl- ------> NaCl
4Al + 3O2------> 2Al2O3
N2+ +3H2 ------> 2NH3
(6,7,8) I can't see the small numbers
Answer:
Excretion or waste elimination
Explanation:
Photosynthesis is a metabolic process carried out by the cells of plant in order to synthesize their own food in form of sugar (glucose). The photosynthetic process combines carbondioxide (CO2), which enters through the STOMATA on their own leaves, and water (H2O) to produce glucose and oxygen gas.
Photosynthesis, which occurs in the Chloroplast organnelle of plant cells, gives off oxygen gas (O2) as a product. The oxygen, which serves as a waste product of photosynthesis, is released from the plant via the same STOMATA openings on their leaves.
The chemical equation is as follows:
6CO2 + 6H2O ----> C6H12O6 + 6O2
Hence, at the organism level (plant), the process of excretion or waste removal is carried out by the plant.
Given question is incomplete. Complete question has been attached.
Answer:
C. Excessive potassium has diffused out causing hyperpolarization.
Explanation:
The nerve action potential can be divided into following stages:
- Stimulus is detected by the cell in resting stage.
- Sodium channels in the membrane open from where influx of sodium ions occur which is called depolarization
- After a while, sodium channels close and potassium channels open from where efflux of potassium ions occur which is called repolarization.
- The membrane potential further lowers due to continous efflux of potassium ions which is called hyperpolarization.
- After a while potassium channels close and membrane returns to its resting stage.
In the given figure, stage 4 depicts hyperpolarization because the membrane potential has dropped to the lowest point below -70mV. Hence, option C is correct.