1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mario62 [17]
3 years ago
14

What is the exact value of

1" title=" \sin(\frac{5\pi}{12} ) " alt=" \sin(\frac{5\pi}{12} ) " align="absmiddle" class="latex-formula">?​
Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
3 0
The answer is: 0.02274421908
You might be interested in
Use the polar representation to write the following in the form a + bi (a) (-1+ i)^7 (b) (1+v3i)^10
ira [324]

Answer with Step-by-step explanation:

For any complex number x+iy the polar form is represented as

z=re^{i\theta }

where

r^{2}=x^2+y^2\\\\tan(\theta )=\frac{y}{x}

Part a) x+iy = -1+i

Thus r=\sqrt{-1^2+1^2}=\sqrt{2}\\\\  \theta _{1}=tan^{-1}(\frac{-1}{1})=\frac{-\pi }{4}

Thus using De-Morvier's theorem

(-1+i)^7=(\sqrt{2}e^{i\frac{-\pi }{4}})^7\\\\\therefore (-1+i)^7=2^{7/2}\cdot e^{\frac{i-\pi }{28}}

Part 2) x+iy = 1+3i

Thus r=\sqrt{1^2+3^2}=\sqrt{10}\\\\  \theta _{1}=tan^{-1}(\frac{3}{1})=1.25

Thus using De-Morvier's theorem

(1+3i)^{10}=(\sqrt{10}e^{1.25i})^{10}\\\\\therefore (1+3i)^{10}=10^{5}\cdot e^{12.5i}

3 0
3 years ago
Can u pls give a clear explanation & word it out how u got the answer without using big words. Thank u
gizmo_the_mogwai [7]

A.

We can rewrite the squared in two ways.

The first way is to rewrite it as a multiplication, this is:

(y-6)^2=(y-6)(y-6)

The second way to rewrite the squared is by using the formula for this kind of product:

(y-6)^2=y^2+2(-6)(y)+(-6)^2

B.

Once again we can find the final result using each of the options given in part A, for the first option we have:

\begin{gathered} (y-6)^2=(y-6)(y-6) \\ =y^2-6y-6y+36 \\ =y^2-12y+36 \end{gathered}

For the second option we have:

\begin{gathered} (y-6)^2=y^2+2(-6)(y)+(-6)^2 \\ =y^2-12y+36 \end{gathered}

No matter which way we choose the answer for the squared is:

y^2-12y+36

3 0
1 year ago
You are considering the purchase of a closed circuit TV monitoring system for your store. The quarterly physical inventory has s
Tcecarenko [31]
If quarterly shrinkage (every 3 months) is 2.5%, then multiplying by $875,495 gives a value of 21887.38, or an average monthly shrinkage of 21887.38 / 3 = $7,295.79.For an employee to monitor the CCTV, it would cost ($7.5/h)(11 h/d)(30 d/m) = $2,475/month. Therefore, it is much cheaper (around 2/3 cheaper) to have an employee monitor CCTV rather than to allow the high shrinkage rate.

7 0
4 years ago
For the point P(21, 24) and Q(26, 27) , find the distance d(P, Q) and the coordinates of the midpoint M of the segment PQ
aleksley [76]

Answer:

d(P,Q) = 5.83 units

Mid-point = (23.5,25.5)

Step-by-step explanation:

Given points are:

P(21,24) = (x1,y1)

Q(26,27) = (x2,y2)

The distance formula is given by:

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Here (x1,y1) are the coordinates of first point and (x2,y2) are coordinates of second point.

Putting the given values in the formula

d(P,Q) = \sqrt{(26-21)^2+(27-24)^2}\\= \sqrt{(5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}

= 5.830952

Rounding off: 5.83 units

The mid-point of two points is given by the formula:

M = (\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2})

Putting the values:

M = (\frac{21+26}{2} , \frac{24+27}{2})\\=(\frac{47}{2} , \frac{51}{2})\\=(23.5, 25.5)

Hence,

d(P,Q) = 5.83 units

Mid-point = (23.5,25.5)

3 0
3 years ago
Math Homework Jim Thompson June 13th
Fittoniya [83]

Answers:

  • 3. E) -0.8
  • 4. True
  • 5. True
  • 6. True
  • 7. D) 17.62%

=========================================

Explanations:

3. We have negative correlation because the regression line is going downhill (move from left to right). The points are fairly close to the same regression line, so I'd say we have either moderate or fairly strong negative correlation. That means r is fairly close to -1. It's not -1 exactly since that would have to mean all points are on the same line.

-----------------

4. Negative correlation goes with negative r values. Refer to problem 3. Positive correlation goes to positive r values. The r value will most likely not equal the slope value, but they share the same sign.

----------------

5. If r is close to +1, then we have fairly strong positive linear correlation. If r is close to -1, then we have fairly strong negative linear correlation. If r = 0 or close to it, then we should use some other kind of regression tool. Or perhaps the data points are simply randomly scattered about and they have no pattern at all.

-----------------

6. Refer to problem 5.

-----------------

7. Plug in x = 15 and you should find that y = -0.632(15)+27.1 = 17.62, which means that the estimated tip is roughly 17.62% of the bill.

8 0
3 years ago
Other questions:
  • (d) Mr. Fowler suggested contacting a travel agent to see whether they could get a lower price. The agent found a price that was
    14·2 answers
  • Solve for y, then find the value of y when given x= -2
    15·1 answer
  • Suppose that 0 < c < π/2. For what value of c is the area of the region enclosed by the curves y = cos(x), y = cos(x − c),
    5·1 answer
  • Solve -3n + 4 ≥ -8. <br> n ≥ 4 <br> n ≤ 4 <br> n ≥ -4<br> n ≤ -4
    9·2 answers
  • Find the reference angle for 497°<br> A) 137°<br> B)133°<br> C) 47°<br> D) 43°
    8·2 answers
  • A car dealership conducted a survey to learn the preferences of their customers. The survey data is shown in the table. Given th
    5·2 answers
  • Christi has $7,500 to invest. She was offered a simple annual interest rate of 4% for three years, but wants to look at other op
    14·1 answer
  • Write the equation 12 = -3x + 6 in the form ax + b = c, with c = 12. What
    7·2 answers
  • A man purchased 6 fruits at Rs 10 How many fruits will he sell at Rs 9 so that he may make an overall profit of 8%
    7·1 answer
  • 3 3/5 x 1 2/3 x 4 2/3
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!