1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Makovka662 [10]
3 years ago
14

What is the symbol for pi?

Mathematics
2 answers:
amm18123 years ago
6 0

Answer:

π

Step-by-step explanation:

Vadim26 [7]3 years ago
6 0
<h2>\displaystyle \pi</h2>
You might be interested in
Plzz i will give brainliest if correct plzzzzzzzzzzzzzzz
GuDViN [60]

Answer:

Umm what do <em>I</em> answer there is nothing there

Step-by-step explanation:

4 0
3 years ago
6+8d=7d solve for d.
Margarita [4]

Question -

6 + 8d = 7d

Solution-

6. = 7d - 8d

6. = -d

d. = -6

<h3>Verification </h3>

6 + 8(-6) = 7(-6)

6 - 48. = -42

-42. = -42

LHS= RHS

Hence value of d is -6

hope it helps

4 0
3 years ago
Read 2 more answers
How write 89,170,326 in expanded and
evablogger [386]

80,000,000+9,000,000+100,000+70,000+300+20+6

8 0
3 years ago
Read 2 more answers
-4 = x -1 can I see you work it out please?
kherson [118]
We need to get x alone, to do that we add 1 to both sides to cancel out the -1 on the right.
-4 = x -1
+1 +1
-3=x

This means x is equal to -3. Hope this helps!
4 0
3 years ago
Read 2 more answers
the half-life of chromium-51 is 38 days. If the sample contained 510 grams. How much would remain after 1 year?​
madam [21]

Answer:

About 0.6548 grams will be remaining.  

Step-by-step explanation:

We can write an exponential function to model the situation. The standard exponential function is:

f(t)=a(r)^t

The original sample contained 510 grams. So, a = 510.

Each half-life, the amount decreases by half. So, r = 1/2.

For t, since one half-life occurs every 38 days, we can substitute t/38 for t, where t is the time in days.

Therefore, our function is:

\displaystyle f(t)=510\Big(\frac{1}{2}\Big)^{t/38}

One year has 365 days.

Therefore, the amount remaining after one year will be:

\displaystyle f(365)=510\Big(\frac{1}{2}\Big)^{365/38}\approx0.6548

About 0.6548 grams will be remaining.  

Alternatively, we can use the standard exponential growth/decay function modeled by:

f(t)=Ce^{kt}

The starting sample is 510. So, C = 510.

After one half-life (38 days), the remaining amount will be 255. Therefore:

255=510e^{38k}

Solving for k:

\displaystyle \frac{1}{2}=e^{38k}\Rightarrow k=\frac{1}{38}\ln\Big(\frac{1}{2}\Big)

Thus, our function is:

f(t)=510e^{t\ln(.5)/38}

Then after one year or 365 days, the amount remaining will be about:

f(365)=510e^{365\ln(.5)/38}\approx 0.6548

5 0
2 years ago
Other questions:
  • Cody wants to attend the fall festival at school.
    14·1 answer
  • Which of the following is not a characteristic of non-Euclidean geometry?
    13·1 answer
  • Any one? I have to finish it today
    12·2 answers
  • How can you an area of triangles and trapezoids
    15·1 answer
  • The rate of change is ____.<br><br>A.-4<br><br>B.-1<br><br>C.1<br><br>D.4
    12·2 answers
  • For a class of 25 students, 5 pizzas are needed for
    15·1 answer
  • Change 1/3 to sixths
    5·2 answers
  • Karen will divide her garden into equal parts. She will plant corn in 8/12 of the garden. What is the fewest number of parts she
    7·1 answer
  • Please help .. Geometry .. No links please!
    5·1 answer
  • What numbers have a sum of 20 and the difference is 4
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!