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mestny [16]
4 years ago
6

What unit is commonly used to measure density

Chemistry
1 answer:
Annette [7]4 years ago
3 0
Kg/m³ is SI unit of density and commonly as gram/mL 
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Which is not a way to separate the components of a mixture?
tresset_1 [31]

Answer:

I think stirring is the right answer

7 0
3 years ago
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How many grams of Fe will be produced if 705.0g of H20 are produced?
fredd [130]
<h3>Answer:</h3>

2265 g Fe₃O₄

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] Fe₃O₄ + 4H₂ → 3Fe + 4H₂O

[Given] 705.0 g H₂O

<u>Step 2: Identify Conversions</u>

[RxN] 4 mol H₂O → 1 mol Fe₃O₄

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Fe - 55.85 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

Molar Mass of Fe₃O₄ - 3(55.85) + 4(16.00) = 231.55 g/mol

<u>Step 3: Convert</u>

  1. Set up stoich:                              \displaystyle 705.0 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O})(\frac{1 \ mol \ Fe_3O_4}{4 \ mol \ H_2O})(\frac{231.55 \ g \ Fe_3O_4}{1 \ mol \ Fe_3O_4})
  2. Multiply/Divide/Cancel units:                                                                           \displaystyle 2264.74 \ g \ Fe_3O_4

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 4 sig figs.</em>

2264.74 g Fe₃O₄ ≈ 2265 g Fe₃O₄

5 0
3 years ago
A geochemist in the field takes a 46.0 mL sample of water from a rock pool lined with crystals of a certain mineral compound X.
inysia [295]

Answer:

The solubility of the mineral compound X in the water sample is 0.0189 g/mL.

Explanation:

Step 1: Given data

The volume of water sample = 46.0 mL.

The weight of the mineral compound X after evaporation, drying, and washing = 0.87 g.

Step 2: Calculate the solubility of X in water

46.00 mL of water sample contains 0.87 g of the mineral compound X.

To calulate how many grams of the mineral compound  1.0 mL  of water sample contains:

0.87 g/46.0 mL = 0.0189 g.

This means the solubility of the mineral compound X in the water sample is 0.0189 g/mL.

3 0
4 years ago
help please thanks you
amid [387]

Answer:

Second option

Explanation:

We started using fossil fuels which are the main cause of climate change

7 0
3 years ago
IM GIVING 30 POINTS PLUS BRAINLIEST FOR CORRECT ANSWERS !!!
ELEN [110]

Answer:

The answer to your question is:

Explanation:

3.- Convert each into

1.56 x 10⁴            =    15600

0.00259 x 10⁵    =        259

0.00259 x 10³    =        2.59

0.56 x 10⁻²         =    0.0056

0.000459 x 10⁻¹    = 0.0000459

0.0209 x 10⁻³    =     0.0000209

3.69 x 10⁻²         =     0.0369

13.69 x 10⁻²        =     0.1369

736.9 x 10⁵        =     73690000

6.9 x 10⁴            =         69000

4.- Calculate the following

a) 2653000 = 2.653 x 10⁶

b) -2687 = - 2.687 x 10³

c) 2.532 x 10²⁴

d) 1470 = 1.47 x 10³

7 0
3 years ago
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