Answer:
The van't hoff factor of 0.500m K₂SO₄ will be highest.
Explanation:
Van't Hoff factor was introduced for better understanding of colligative property of a solution.
By definition it is the ratio of actual number of particles or ions or associated molecules formed when a solute is dissolved to the number of particles expected from the mass dissolved.
a) For NaCl the van't Hoff factor is 2
b) For K₂SO₄ the van't Hoff factor is 3 [it will dissociate to give three ions one sulfate ion and two potassium ions]
Out of 0.500m and 0.050m K₂SO₄, the van't hoff factor of 0.500m K₂SO₄ will be more.
c) The van't Hoff factor for glucose is one as it is a non electrolyte and will not dissociate.
Answer:
A) he equilibrium concentration of PH3 = 0.0432M
B) he equilibrium concentration of BCl3 = 0.0432M
C) what is the minimum mass of PH3BCl3(s) that must be added to the flask to achieve equilibrium = 1.69g
Explanation:
The detailed steps and appropriate calculation is as shown in the attached file.
Answer:
78.125ml
Explanation:
Number of moles in 250ml of 2.5M KCl is (250÷1000)litres×2.5M so we divide these moles by 8M. The answer gotten will be in litres so multiply by 1000 to get it in ml
<h3>
Answer:</h3>
D. CH₃O₆
<h3>
Explanation:</h3>
- We are given the ratio of carbon, hydrogen and oxygen in a compound as 14: 42 : 84
We are supposed to determine the empirical formula of the compound;
- We need to know what is an empirical formula;
- An empirical formula of a compound is a formula that shows the simplest whole number ratio of elements in a compound.
In this case;
The ratio of C : H : O is 14 : 42 : 84
- Note, this is not the simplest ratio.
But we can simplify further to get the simplest whole number ratio;
- Therefore, 14 : 42 : 84 is equal to 1 : 3 : 6
- Thus, the simplest whole number ratio of C : H : O in the compound is 1 : 3 : 6
- Therefore, the empirical formula of the compound is CH₃O₆
