The amount of substance that is present after t years given that the half-life of the substance is h is calculated through the equation,
A(t) = A(o)(0.5^t/h)
If after a year, the rate of decay is equal to 33.3% then,
A(t)/A(o) = (1/3) = 0.5^(1/h)
The value of h from the equation is 0.63 years.
Answer: 0.63 years
According to the research, fatty acids, which are long molecules in the form of a hydrocarbon chain, are a component of lipids.
<h3>What are lipids?</h3>
They are hydrophobic and water-insoluble molecules that are formed from the esterification of alcohols with fatty acids.
Lipids are a vital part of the diet of living beings since many vitamins are assimilated in the presence of certain lipids and many fatty acids are essential for animal metabolism.
Therefore, we can conclude that according to the research, fatty acids, which are long molecules in the form of a hydrocarbon chain, are a component of lipids.
Learn more about the lipids here: brainly.com/question/17352723
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Answer: -
13.545
Explanation: -
Let the volume of the solution be 1000 mL
Density = 1.04 g/ mL
Mass = density x vol
= 1.04 g/ mL x 1000 mL
= 1040 g
Amount of NaOH = 
x 1040 g
= 14.04 g
Molar mass of NaOH = 23 x 1 + 16 x 1 + 1 x 1
= 40 g / mol
Number of moles = Amount of NaOH / Molar mass
= 14.04 /40
= 0.351 mol
So 1000 ml of the solution has 0.351 mol
Molarity of NaOH = 0.351 M
Using the relation
pOH = - log [OH-]
= - log 0.351
= 0.455
Using the relation pH + pOH = 14
pH = 14 - pOH
= 14 - 0.455
= 13.545
Answer:
Postassium bisulphate - KHSO4 - can be used as an food preservative to protect the food from micro-organisms.
