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3 years ago

What is the density of a 10 kg mass that occupies 5 liters? ( pls need help)

Chemistry

1 answer:

bulgar [2K]3 years ago

7 0

Answer: d=2000 g/L

Explanation:

Density is mass/volume. The units are g/L. Since we are given mass and volume, we can divide them to find density. First, we need to convert kg to g.

$10kg*\frac{1000g}{1kg} =10000 g$

Now that we have grams, we can divide to get density.

$d=\frac{10000g}{5 L}$

d=2000g/L

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Which roles belong to decomposers? Check all that apply.

Crank

Answer:Decomposers break down waste and dead organisms.

Explanation:

Decomposers help keep the environment clean by acting on waste

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4 years ago

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Determine how much energy is needed to change 50 g of liquid water at 100°C to steam.

marin [14]

Answer:

$Q=113,000J$

Explanation:

Hello there!

In this case, since the vaporization process is carried out in order to turn a liquid into a gas due to the addition of heat, we can use the following heat equation involving the heat of vaporization of water or any other substance:

$Q=m*\Delta _{vap}H$

Thus, since this heat of vaporization for water is 2259.36 J/g, we plug in this amount to obtain the total energy for this process.

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3 years ago

A mixture was found to contain 1.05 g if silicone dioxide, 0.69 g cellulose, 1.82 g of calium carbonate. what percent of calcium

djverab [1.8K]

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3 years ago

What mass of solid lead would displace exactly 234.6 liters of water?

eimsori [14]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

The mass of solid lead would displace exactly 234.6 liters of water should be <span>2,674,440</span>

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3 years ago

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What is the mass of a sample of water that takes 2000 kJ of energy to boil into steam at 373 K. The latent heat of vaporization

zzz [600]

Answer:

$\boxed{\text{889 g}}$

Explanation:

The formula relating the mass m of a sample and the heat q to vaporize it is

q = mL, where L is the latent heat of vaporization.

$\begin{array}{rcl}2000 \times 10^{3} \text{ J} & = & m \times \dfrac{2.25 \times 10^{6} \text{ J}}{\text{1 kg}}\\\\m & = & \dfrac{2000 \times \times 10^{3}\text{ kg}}{2.25 \times 10^{6}}\\ & = & \text{0.889 kg}\\\\ & = & \text{889 g}\\\end{array}\\\text{The mass of water is $\boxed{\textbf{889 g}}$}$

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3 years ago