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Nataly_w [17]
3 years ago
5

What is the answer to (z+1)(z+2)

Mathematics
2 answers:
Marrrta [24]3 years ago
8 0

Answer:

Step-by-step explanation:

(z+1)(z+2) = z²+2z+z+2 =z²+3z+2

stich3 [128]3 years ago
4 0

Answer:

z^1+3z+2

Step-by-step explanation:

(z+1)(z+1)

Multiply each term in the first parenthesis by each term in the second parenthesis

Z x z+2z+z+2

Calculate the product

<u>z</u>^2 +2z+z+2

collect like terms

z^2+3z+2

2z+z

If a term doesnt have a coefficient it is considered that the coefficient is 1

2z+1z

(2+1)z

(2+1)z

3z

z^2+3z+2

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3 - 1/8a = 1/4

The goal is to isolate "a" and its coefficient to make the simplification process easier.

Start by subtracting 3 from both sides:

3 - 3 - 1/8a = 1/4 -3

-1/8a = 1/4 - 3

Next, multiply 3 by 4/4 to convert it into a fraction:

-1/8a = 1/4 - [3 • (4/4)]

-1/8a = 1/4 - 12/4

-1/8a = - 11/4

Multiply both sides by -8:

(-8) -1/8a = - 11/4 (-8)

a = 88/4 = 22

Therefore, a = 22.
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