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Bess [88]
3 years ago
13

Which equation does not represent a function?

Mathematics
1 answer:
kati45 [8]3 years ago
8 0

Answer:

D x2 + y2 = 4

Step-by-step explanation:

The following are the functions

y = 4

y = x - 4

y = x^2 - 4

but

x^2 + y^2 = 4 is not a function as there should be minimum one x value with two or more y values

But the above equation does not meet the criteria so this represent non-function

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Hey! :)

Some things to note: When you bring a exponent to the numerator, you make it negative.

When you put an exponent to another exponent, you multiply the exponents together.

(\frac{3x^2y^5}{x^6y^2} )^4\\\frac{81x^8y^{20}}{x^{24}y^8}\\81x^8x^{-24}y^{20}y^{-8}\\\frac{81y^{12}}{x^{16}}

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Rashid [163]

\\ \sf\longmapsto 2(L+B)=55

\\ \sf\longmapsto 2(\dfrac{4}{3}x+x)=55

\\ \sf\longmapsto \dfrac{8}{3}x+2x=55

\\ \sf\longmapsto \dfrac{8x+6x}{3}=55

\\ \sf\longmapsto \dfrac{14x}{3}=55

\\ \sf\longmapsto 14x=165

\\ \sf\longmapsto x=11.78

\\ \sf\longmapsto x\approx 12

Now

  • B=x=12
  • L=4/3(12)=4(4)=16
5 0
2 years ago
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What value of x will make triangles ABM and DCM<br> congruent?<br> 3<br> 5<br> 7<br> 9
kykrilka [37]
The congruent side is going to be 9
6 0
2 years ago
I need graph help plz ​
Likurg_2 [28]

Answer:

Step-by-step explanation:

Part A

x-intercepts of the graph → x = 0, 6

Maximum value of the graph → f(x) = 120

Part B

Increasing in the interval → 0 ≤ x ≤ 3

Decreasing in the interval → 3 < x ≤ 6

As the price of goods increase in the interval [0, 3], profit increases.

But in the price interval of (3, 6] profit of the company decreases.

Part C

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Average rate of change = \frac{f(b)-f(a)}{b-a}

Therefore, average rate of change of the function in the interval x = 1 and x = 3 will be,

Average rate of change = \frac{f(3)-f(1)}{3-1}

                                         = \frac{120-60}{3-1}

                                         = 30

6 0
3 years ago
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