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pogonyaev
3 years ago
9

If 5 4, − = x then x = A. −21 B. −11 C. 1 D. 11

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
4 0
5 - x = 4
Subtract x from both sides.
5 - x + x = 4 + x
5 = 4 + x
Subtract 4 from both sides.
5 - 4 = 4 + x - 4
Hence, the answer:

x = 1
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The left and right page numbers of an open book are two consecutive integers whose sum is 195
marusya05 [52]

Answer:

97, 98

Step-by-step explanation:

a = first number

a + 1 = consecutive number

then:

a + a+1 = 195

2a + 1 = 195

2a = 195 - 1

2a = 194

a = 194/2

a = 97

a + 1 = 98

Check:

97 + 98 = 195

8 0
2 years ago
What are benchmarks when using rounding?
cricket20 [7]

Answer:

Benchmark can be defined as the standard or reference point against which something can be measured, compared, or assessed.

Step-by-step explanation:

7 0
3 years ago
In the orthonormal system (O; i⃗,j⃗) below, consider point A(3, −1), vector v⃗(2,1), and
Akimi4 [234]

Answer:

Step-by-step explanation:

8 0
3 years ago
Solve this system of linear equations. separate the x- and y- values with a coma. -12x=-75-11y
ycow [4]
Solve the following system:
{-12 x = -11 y - 75 | (equation 1)
{-5 x = -11 y - 89 | (equation 2)
Express the system in standard form:
{-(12 x) + 11 y = -75 | (equation 1)
{-(5 x) + 11 y = -89 | (equation 2)
Subtract 5/12 × (equation 1) from equation 2:
{-(12 x) + 11 y = -75 | (equation 1)
{0 x+(77 y)/12 = (-231)/4 | (equation 2)
Multiply equation 2 by 12/77:
{-(12 x) + 11 y = -75 | (equation 1)
{0 x+y = -9 | (equation 2)
Subtract 11 × (equation 2) from equation 1:
{-(12 x)+0 y = 24 | (equation 1)
{0 x+y = -9 | (equation 2)

Divide equation 1 by -12:
{x+0 y = -2 | (equation 1)
{0 x+y = -9 | (equation 2)
Collect results:
Answer:  {x = -2                {y = -9

please note that the parentheses "{" should span over both equations but the editor doesn't allow that so I should it on both line, See attached example.










4 0
3 years ago
ABCD is a parallelogram. AB>AD. Prove: m∠ADB>m∠BDC. Show your work (statement reason maybe?)
Gwar [14]

In the parallelogram ABCD, join BD.

Consider the triangle Δ ABD.

It is given that AB > AD.

Since, in a triangle, angle opposite to longer side is larger, we have,

∠ ADB > ∠ ABD. --- (1)

Also, AB || DC and BD is a transversal.

Therefore,

∠ ABD = ∠ BDC

Substitute in (1), we get,

∠ ADB > ∠ BDC.

7 0
3 years ago
Read 2 more answers
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