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marta [7]
3 years ago
5

Express the complex number in trigonometric form. square root of 3+2i

Mathematics
1 answer:
Zinaida [17]3 years ago
8 0
\bf \begin{array}{llll}
\sqrt{3}&,&2i\\
\uparrow &&\uparrow \\
a&&b
\end{array}\implies r[cos(\theta )+i\ sin(\theta )]\qquad 
\begin{cases}
r=\sqrt{a^2+b^2}\\
\theta =tan^{-1}\left( \frac{b}{a} \right)
\end{cases}
\\\\\\
r=\sqrt{(\sqrt{3})^2+(2)^2}\implies r=\sqrt{3+4}\implies r=\sqrt{7}
\\\\\\
\theta =tan^{-1}\left( \frac{2}{\sqrt{3}} \right)\implies \theta \approx 49.10660535^o\textit{ or just 49 rounded up}\\\\
-------------------------------\\\\
\sqrt{3},2i\implies \sqrt{7}[cos(49^o)+i\ sin(49^o)]
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5 and negative 5

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The absolute value is the distance from 0 five and negative 5 are both the same distance from zero

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If the weight of a package is multiplied by 5/7 the result is 40.5 pounds. Find the weight of the package.
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Can someone help me with this problem://
fiasKO [112]

You can simply collect terms, subtract the constant and divide by the x-coefficient. It is generally considered easier to do those steps if you eliminate fractions first (multiply by 12).

Multiply by 12

... 4(x -1) +3(x +5) = 6

... 4x -4 +3x +15 = 6 . . . . . eliminate parentheses

... 7x +11 = 6 . . . . . . . . . . . .collect terms

... 7x = -5 . . . . . . . . . . . . . . subtract the constant 11

... x = -5/7 . . . . . . . . . . . . . divide by the x-coefficient

_ _ _ _ _ _ _

Here it is the other way.

... x(1/3 +1/4) +(-1/3 +5/4) = 1/2

... (7/12)x + 11/12 = 1/2 . . add the fractions to finish collecting terms

... x + 11/7 = 6/7 . . . . . . . multiply by 12/7

... x = -5/7 . . . . . . . . . . . subtract 11/7

At the third step here, you could subtract 11/12 before doing the multiply. You get the same answer, but you have to do the extra conversion of 1/2=6/12.

8 0
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