how many miles on 1 gallon?
Lauren: 320/10=32
Melissa:280/8=35
Who Drove farther?
32*40=1280
35*40=1400
Melissa can drive farther
You have to calculate the expected value of pulling any number of good batteries.
There are 3 bad batteries (B) and seven good batteries (G)
If you pull two batteries the possible number of good batteries you can get are 0, 1 and 2.
GB, BG, GG, and BB
two chances for getting 1, one chance for getting two, and one chance for getting zero.
In order to calculate the expected value you have to first calculate the values of all the possibilities.
(GB = 7/10 x 3/10) (BG = 3/10 x 7/10) (GG = 7/10 x 7/10) (BB = 3/10 x 3/10)
Then take these answers and multiply them by the number of good batteries they each contain and add. (GB is 1 good battery, GG is two, etc.)
1(.21) + 1(.21) + 2(.49) + 0(.09)
The result is 1.4
The expected value of good batteries is 1.4
Answer:
Step-by-step explanation:
f(x) = x^3 - 6x^2 + 11x - 6
By the Rational Roots theorem, the roots will be among ±1,2,3,6
So try the low-hanging fruit first. It is clear that f(1) = 0. So, factoring that out, you have
f(x) = (x-1)(x^2-5x+6)
Now factor the quadratic in the usual way.
