Answer:
Solving for x gives x=7
Step-by-step explanation:
First lets rewrite our equation clear, which from the question reads as :
Eqn(1).
This is a case of an equation with one variable <em>(i.e. one uknown)</em> denoted as
.
The question is asking as to solve this equation and obtain the value of
.
To do so we start by rewriting and simplifying the equation as follow: ![(x-1)\frac{1}{3}=2](https://tex.z-dn.net/?f=%28x-1%29%5Cfrac%7B1%7D%7B3%7D%3D2)
which is the same as
![\frac{(x-1)}{3}=2](https://tex.z-dn.net/?f=%5Cfrac%7B%28x-1%29%7D%7B3%7D%3D2)
Here we have a fraction on the left hand side reading as
and an integer on the right hand side as
. Thus we move the denominator of the fraction, in this case
to the right hand side where we multiply it with
, to eliminate our fraction and solve for
as follow:
![x-1 =2*3\\x-1=6\\x=6+1\\x=7](https://tex.z-dn.net/?f=x-1%20%3D2%2A3%5C%5Cx-1%3D6%5C%5Cx%3D6%2B1%5C%5Cx%3D7)
(Note how we transferd
from the left hand side to the right hand side, the sign changed from <em>negative </em>to <em>positive). </em>
To keep track of something cause I use context clues and it was table
Answer:
Each pair of alternate interior angles is congruent, and each pair of alternate exterior angles is congruent.
Step-by-step explanation:
The expression is given as,
![\frac{1}{2}+\frac{1}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%2B%5Cfrac%7B1%7D%7B3%7D)
Note that the denominator of both the fractions are prime numbers. So their lowest common multiple, LCM(2,3) will be the product of the numbers,