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navik [9.2K]
2 years ago
6

PLEASE HELP ME ASAP!!!!!!!!!!!!!!!!!!!!!!!!! 3) This problem is called the Collatz Conjecture and is an unproven statement in ma

thematics. People have used computers to try all the numbers up to 5×260 and many mathematicians believe it to be true, but since all natural numbers are infinite in number, this test does not constitute a proof.
Consider the following pattern generating rule:

If the last number is odd, multiply it by 3 and add 1.

If the last number is even, divide the number by 2.

Repeat.

Show a few different starting numbers and see if you can state what you think always happens. Show at least two different representations.

4) Suppose the Fibonacci sequence started with 2 and 5.

a) List the first 10 terms of the new sequence.

b) Find the sum of the first 10 terms of the new sequence
Mathematics
1 answer:
Aneli [31]2 years ago
7 0

The set of numbers in the Collatz Conjecture are 1, 4, 2, 1, 4, 2, 1, 4, 2....

<h3>How to generate the numbers in the Collatz Conjecture</h3>

To start with, we make use of the following starting point:

Starting point = 1

The rule is given as:

  • If the last number is odd, multiply it by 3 and add 1.
  • If the last number is even, divide the number by 2.

1 is an odd number.

So, we use the first rule

So, we have:

1 * 3 + 1 = 4

4 is an even number.

So, we use the second rule

So, we have:

4/2 = 2

So, the first three numbers in the Collatz Conjecture are:

1, 4, 2

Using the given rules, we have:

1, 4, 2, 1, 4, 2, 1, 4, 2....

The above means that there is only one set of repeating numbers in the Collatz Conjecture.

Hence, the set of numbers in the Collatz Conjecture are 1, 4, 2, 1, 4, 2, 1, 4, 2....

<h3>Fibonacci sequence</h3>

The first and the second numbers are given as:

First = 2

Second = 5

The current term of a Fibonacci sequence is the sum of the previous two terms.

Using the above rule, the first 10 terms are:

2, 5, 7, 12, 19, 31, 50, 81, 131, 212

<h3>The sum of the first 10 terms of the new sequence</h3>

We have:

2, 5, 7, 12, 19, 31, 50, 81, 131, 212

Add the terms

Sum = 2+ 5+ 7+ 12+ 19+31+50+81+131+212

Evaluate

Sum = 550

Hence, the sum of the first 10 terms of the new sequence is 550

Read more about sequence at:

brainly.com/question/7882626

#SPJ1

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Korvikt [17]
10 mm = 1 cm, so 

35.7 mm = 35.7/10 = 3.57 cm

b.
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3 years ago
Marigold Industries collected $104,000 from customers in 2019. Of the amount collected, $24,400 was for services performed in 20
m_a_m_a [10]

Answer:

\text{Net accrual income}=\$31,600

Step-by-step explanation:

We have been given that Marigold Industries collected $104,000 from customers in 2019. Of the amount collected, $24,400 was for services performed in 2018. In addition, Marigold performed services worth $39,000 in 2019, which will not be collected until 2020.

Let us find revenue earned in 2019 by subtracting revenue earned from 2018 and adding revenue earned in 2019 to total revenue as:

\text{Revenue in 2019}=\$104,000-\$24,400+\$39,000

\text{Revenue in 2019}=\$118,600

Marigold Industries also paid $73,900 for expenses in 2019. Of the amount paid, $29,100 was for expenses incurred on account in 2018. In addition, Marigold incurred $42,200 of expenses in 2019, which will not be paid until 2020.

Now, we will find expenses in 2019 by subtracting expenses in 2018 and adding expenses in 2019 to total expenses as:

\text{Expenses in 2019}=\$73,900-\$29,100+\$42,200

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To find accrual net-income, we will subtract$87,000 from $118,600 as:

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2 years ago
How much is 19.5% of 600?
MakcuM [25]
19.5% of 600 is 117.            
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Read 2 more answers
1. Find two numbers with a common factor of 3 only.
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Answer:

All numbers can be written as a product of the prime numbers that conform them.

A) Find two numbers with a common factor of 3 only.

for example:

2*3 = 6

7*3 = 21

Both numbers have the factor 3 in them, and because the other two numbers are primes, we can be sure that the 3 is the only common factor.

B) Write a pair of numbers with a common factor of 2, 3 and  6.

Here we can write:

2*3*2 = 12

3*2*5 = 30

Those two numbers have the common factors 6, 2 and 3.

C) Write a pair of numbers with common factors of 3, 6 and  9.​

3*2*3 = 18 (has the factors 2, 3, 3*2 = 6, 3*3 = 9)

-3*2*6 = -36

Both have the common factors 3, 6 and 9 (and they share more common factors like 2, this happens because 6 = 3*2, so if 6 is a common factor, 2 also must be)

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Based on my calculations, this would be 10%.
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