Answer:
xy
Step-by-step explanation:
Let's take a look at what factors
and
have in common.
is composed of
and y, and
is composed of x and
. Notice that both x and y are factors of them, so the gcf is xy.
Answer:
(A)
Step-by-step explanation:
Using the formula :
Area = 1/2 [-1(1 - 6) -7(6 - 1) -3(1 - 1)]
Area = 1/2 [5 - 35]
Area = 1/2 × -30 = |-15| = 15 units²
120/6=20 20*10=200
The answer is 200
Answer:
There is a 0.82% probability that a line width is greater than 0.62 micrometer.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.
In this problem
The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so
.
What is the probability that a line width is greater than 0.62 micrometer?
That is 
So



Z = 2.4 has a pvalue of 0.99180.
This means that P(X \leq 0.62) = 0.99180.
We also have that


There is a 0.82% probability that a line width is greater than 0.62 micrometer.
Answer: 70.909090909091%
Step-by-step explanation: Reading through the problem we have <em>78 is</em>, that's 78 equals, <em>what percent</em>, x/100, <em>of 110</em>, times 110.
It's important to understand that <em>percent</em> means over 100 so what percent would simply mean <em>x/100</em> or any variable but I will be using x.
So we have the equation 
So cross canceling the 110 and 100 to 11 and 10, we have 
Multiply both sides by 10 to get rid
of the fraction and we have 780 = 11x.
Now divide both sides by 11 and 70.909090909091 = x.
So, 78 is 70.909090909091% of 110.
Work is attached in the image provided.