Answer:
89/16
Step-by-step explanation:
Using the z-distribution, a sample of 142,282 should be taken, which is not practical as it is too large of a sample.
<h3>What is a z-distribution confidence interval?</h3>
The confidence interval is:

The margin of error is:

In which:
is the sample mean.
is the standard deviation for the population.
Assuming an uniform distribution, the standard deviation is given by:

In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of
, so the critical value is z = 1.96.
The sample size is found solving for n when the margin of error is of M = 0.006, hence:





n = 142,282.
A sample of 142,282 should be taken, which is not practical as it is too large of a sample.
More can be learned about the z-distribution at brainly.com/question/25890103
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81 is a counter example of the conditional statement given.
81 has factors other than itself, 1 and the square root of 81 which is 9.
81 has factors of 3 and 27 which are not listed.
Answer:153
Step-by-step explanation:
From the question, we are informed that Emilio asks his classmates what month they were born and that he finds that 15 out of 125 classmates were born in July. This gives us a fraction of 15/125 = 3/25.
If there are 1,280 students in Emilio's school, the number of students that he can expect to have birthdays in July would be:
= 3/25 × 1280
= 153.6
There will be 153 students expected
Tan 2 x-2 tan x=0
Tan x (tan x-2 ) =0
A tan x=0 —> x=0 and x =K π
B tan x=2 —> x=63.43 +k180 deg