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Fittoniya [83]
3 years ago
5

Team A walks at a constant rate of 2.5 miles per hour

Mathematics
1 answer:
iren [92.7K]3 years ago
8 0
Can't understand. What part is the question?
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Watching tv: in 2012, the general social survey asked a sample of 1310 people how much time they spend\t watching tv each day. T
garik1379 [7]

Answer:

a) Null hypothesis:\mu \geq 3  

Alternative hypothesis:\mu < 3  

This hypothesis test is a left tailed test.

b) t=\frac{2.8-3}{\frac{2.6}{\sqrt{1310}}}=-2.784  

The p value for this case can be calculated with this probability:  

p_v =P(z  

We can conduct the test with the Ti84 using the following steps:

STAT>TESTS>T-test>Stats

We input the value \mu_o =3, \bar X= 2.8, s_x = 2.6, n=1310 and for the alternative we select < \mu_o. Then press Calculate.

And we got the same results.  

Step-by-step explanation:

Information given

\bar X=2.8 represent the sample mean

s=2.6 represent the population standard deviation  

n=1310 sample size  

\mu_o =3 represent the value to test

\alpha=0.5 represent the significance level for the hypothesis test.  

t would represent the statistic

p_v represent the p value for the test

Part a) System of hypothesis

We want to test if the true mean is less than 3, the system of hypothesis would be:  

Null hypothesis:\mu \geq 3  

Alternative hypothesis:\mu < 3  

This hypothesis test is a left tailed test.

Part b

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

Replacing the info given we got:

t=\frac{2.8-3}{\frac{2.6}{\sqrt{1310}}}=-2.784  

The p value for this case can be calculated with this probability:  

p_v =P(z  

We can conduct the test with the Ti84 using the following steps:

STAT>TESTS>T-test>Stats

We input the value \mu_o =3, \bar X= 2.8, s_x = 2.6, n=1310 and for the alternative we select < \mu_o. Then press Calculate.

And we got the same results.  

3 0
2 years ago
NEED ANSWERS TO 25 APSPSLANDEBEB PLEASE
ahrayia [7]
Answer:
New point location is (2,0)

Explanation:
I’ve attached my work
Hope it helps, let me know if you have any questions !

5 0
2 years ago
In ΔHIJ, the measure of ∠J=90°, HI = 8 feet, and JH = 1.9 feet. Find the measure of ∠H to the nearest tenth of a degree.
artcher [175]

Answer:

21.9°

Step-by-step explanation:

In ΔHIJ, the measure of ∠J=90°, HI = 8 feet, and JH = 1.9 feet. Find the measure of ∠H to the nearest tenth of a degree.

We solve this above question using the Sine rule

a/sin A = b/sin B

In ΔHIJ, the measure of ∠J=90°, HI = 8 feet, and JH = 1.9 feet.

Hence:

HI/∠J = JH/∠H

= 8/sin 90° = 1.9/sin ∠H

Cross Multiply

∠H = arc sin(sin 1.9 × 90/8)

∠H = 21.9°

5 0
2 years ago
Which of the following approaches would be an appropriate first step? select all that apply​
Eva8 [605]

Answer:

Divide both sides by -1/3, Apply distributive property, add 1/3 to both sides

Step-by-step explanation:

If its confusing just replace -1/3 with a simple number such as -1, to make it make sense.

4 0
2 years ago
What is the product of 136.4 and 0.47?
solniwko [45]

Answer:

64.108

136.3x0.47=64.108

i did it ona calculator

5 0
3 years ago
Read 2 more answers
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