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postnew [5]
3 years ago
8

How does the graph of f(x)=1/x compare to the graph of g(x)=4f(x)?

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
4 0

Answer:

  vertically compressed by a factor of 4

Step-by-step explanation:

The multiplier of 4 in the definition of g(x) means it is an expansion vertically by a factor of 4 of the graph of f(x). Then, ...

  f(x) is a vertical compression by a factor of 4 of g(x)

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I need help plz ???
jasenka [17]

Answer: M=-2 , B= 2 , Equation: Y= -2x+2

Step-by-step explanation:

M is the slope. Slope is "rise / run", so 2 over -1. simplified, that is -2. B is the y-intercept, or where the graph crosses the y-axis. So, b will be 2.

8 0
3 years ago
Rewrite the equation below so that it does not have fractions 2+2/3x=3/4
miv72 [106K]

Answer:

9x = 16

Step-by-step explanation:

2+2/3x=3/4

4/3x = 3/4

3x/4  = 4/3

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8 0
2 years ago
The steps for solving the equation 2x-3=7
saw5 [17]

Step 1: Add 3 to both sides.

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3 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!!! CORRECT ANSWERS FOR BOTH PART 1 AND 2 ONLY PLEASE!!!
professor190 [17]

1. Answer: Vertical shift up 3 units and vertical stretch by factor of 2

<u>Step-by-step explanation:</u>

f(x) = √x

g(x) = 2√x + 3  

  • adding 3 is a vertical shift up 3 units
  • multiplying by 2 is a vertical stretch by factor of 2

2. Answer: Domain: [0, ∞)

                   Range: [3, ∞)

<u>Step-by-step explanation:</u>

g(x) = 2√x + 3  

Domain: The restriction on "x" is that the radical must be greater than or equal to 0.  So, x ≥ 0  Interval Notation: [0, ∞)

Range: Since the radical must be greater than or equal to 0, then 2√x is also greater than or equal to 0.  Add 3 to that and y ≥ 3.  Interval Notation: [3, ∞)

8 0
2 years ago
Please help with 3. 4. 5.
Eddi Din [679]
3.
\text{The Triangle Sum Theorem:}\\m\angle A+m\angle B+m\angle C=180^o
x+2x-1+3x+1=180\\6x=180\ \ \ |:6\\x=30
x^o=30^o\\(3x+1)^o=(3\cdot30+1)^o=91^o\\(2x-1)^o=(2\cdot30-1)^o=59^o
4.
r-6+3r-3+5r=180\\9r-9=180\ \ \ |+9\\9r=189\ \ \ |:9\\r=21
(r-6)^o=(21-6)^o=15^o\\(3r-3)^o=(3\cdot21-3)^o=60^o\\(5r)^o=(5\cdot21)^o=105^o
5.
\text{The Exterior Angle Theorem:}\\m\angle CAB+m\angle ABC=m\angle DCB
2g+9g=110\\11g=110\ \ \ |:11\\g=10
m\angle A=2\cdot10^o=20^o\\m\angle ACB=180^o-110^o=70^o\\m\angle B=9\cdot10^o=90^o
4 0
3 years ago
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