We know that 24 is 160% more than some recommended number, let's call it "x." This means 1.6 times the recommended number equals 24. Therefore, all we need to do is solve for x.
Make sense?
Hi, I actually just took the test and got 100%
Remember: When plotting the points for this equation, make sure to always first plot the ones that correspond to the first linear equation, and then plot the ones that correspond to the second linear equation.
The points on the line should be for the first linear equation, (4,0) and (8,0). I got this answer by first converting the linear equation, 2x+y=8 from standard form to slope-intercept form. To do this, I subtracted 2x from both sides of the equation. So now it reads as y=8-2x. After this step was completed, I then graphed my first linear equation.
The points on the line should be for the first linear equation, (2,4) and (6,6).
I got this answer by first converting the linear equation, -x+2y=6 into slope-intercept form. To do this, I subtracted -x from both sides of the equation. Then I had to divide the 2 into both -x and 6. So now it reads as y= 6/2-x/2. After this step was completed, I then graphed my second and final linear equation.
I hope this helps!
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Answer:
The triangle is not acute because 2² + 4² < 5²
Step-by-step explanation:
The square of the hypotenuse of a right triangle with the given short sides would be 2² +4² = 20. So, that hypotenuse would be √20, about 4.47. The long side of this triangle is longer than that, so the angle opposite is larger than 90°. The triangle with sides 2, 4, 5 is an obtuse triangle.
The triangle is not acute because 2² + 4² < 5²
Answer:
-a/(x+b)²
Step-by-step explanation:
Given the function y = a/x+b
To differentiate, we will use the quotient rule.
dy/dx = (Vdu/dx-Udv/dx)/V²
Let u = a
v = x+b
Note that differential of a constant is zero
du/dx = 0
dv/dx = 1
Substitute
dy/dx = (x+b)0 - a (1)/(x+b)²
dy/dx = 0 - a/(x+b)²
dy/dx = -a/(x+b)²
Answer:
t = 63/50 , t = 1.26, t = 1 13/50
Step-by-step explanation:
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