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Deffense [45]
2 years ago
5

A square has an area of 100 square meters. What is the perimeter of the square?

Mathematics
1 answer:
LiRa [457]2 years ago
5 0

Answer:

40 square meters

Step-by-step explanation:

Perimeter means to add up all sides.

area means one side times one side

10 times 10 makes 100 so i am guessing each side is 10

10 + 10 + 10 + 10 = 40

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What is 5.8 × 10^6 mg/s in grams per minute?
Margaret [11]
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4 0
3 years ago
A company spends $80 to set up their printer
Setler79 [48]

Answer:

The Answer is Option D.

Step-by-step explanation:

The Company spends $80 on the printer so whatever amount of shirts multiplied by $10 each should be subtracted by 80. There should also be a greater than or equal to symbol to the left side of the equation to show it can be 200 dollars or more. This matches Option D. Plz Give Brainliest and have a good day!

6 0
3 years ago
BRAINLIESTTTTTTTTTTTT!! :)
skad [1K]
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Have A Good Day :)
3 0
3 years ago
Read 2 more answers
Suppose that surface σ is parameterized by r(u,v)=⟨ucos(3v),usin(3v),v⟩, 0≤u≤7 and 0≤v≤2π3 and f(x,y,z)=x2+y2+z2. Set up the sur
Bad White [126]

Looks like you have most of the details already, but you're missing one crucial piece.

\sigma is parameterized by

\vec r(u,v)=\langle u\cos3v,u\sin3v,v\rangle

for 0\le u\le7 and 0\le v\le\frac{2\pi}3, and a normal vector to this surface is

\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\left\langle\sin3v,-\cos3v,3u\right\rangle

with norm

\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=\sqrt{\sin^23v+(-\cos3v)^2+(3u)^2}=\sqrt{9u^2+1}

So the integral of f(x,y,z)=x^2+y^2+z^2 is

\displaystyle\iint_\sigma f(x,y,z)\,\mathrm dA=\boxed{\int_0^{2\pi/3}\int_0^7(u^2+v^2)\sqrt{9u^2+1}\,\mathrm du\,\mathrm dv}

6 0
2 years ago
A fishbowl has a capacity of 192 fluid ounces. How many quarts is that?
DENIUS [597]

Answer:

hope this helps

Step-by-step explanation:

192 fl oz. = 6 quarts

to get this you divide the fluid ounces by 32.

7 0
2 years ago
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